Sketching graphWatch

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Thread starter 1 year ago
#1
What sort of transformation does the graph of y=e^x undergoes to get to y=1/(e^x +2) ? I have plotted both graphs but can’t seem to figure what transformations happened after y=1/e^x.
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1 year ago
#2
(Original post by Janej77)
What sort of transformation does the graph of y=e^x undergoes to get to y=1/(e^x +2) ? I have plotted both graphs but can’t seem to figure what transformations happened after y=1/e^x.
That transformation is not a linear one.
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Thread starter 1 year ago
#3
(Original post by RDKGames)
That transformation is not a linear one.
Does this mean that to plot the graph, it would be easier for me to work out few points on the graph and then plot it? The Cartesian equation I’ve got here is from two parametric equations.
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1 year ago
#4
(Original post by Janej77)
Does this mean that to plot the graph, it would be easier for me to work out few points on the graph and then plot it? The Cartesian equation I’ve got here is from two parametric equations.
Yeah it would be easier to do that, and some analysis, rather than thinking about the linear transformations.

For instance, as this equation approaches .

As this equation approaches .

So the curve has two horizontal asymptotes.
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1 year ago
#5
(Original post by Janej77)
What sort of transformation does the graph of y=e^x undergoes to get to y=1/(e^x +2) ? I have plotted both graphs but can’t seem to figure what transformations happened after y=1/e^x.
You can sketch e^x+2?
Draw the line y = 1
The curve "y" you want is such that y*(e^x+2) = 1
So if
e^x+2 = 2 then y = 1/2
e^x+2 = 3 then y = 1/3
e^x+2 = 10 then y = 1/10 ...
1
Thread starter 1 year ago
#6
Thank you all for your help and your time. I have managed to sketch out the graph correctly.
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