Janej77
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What sort of transformation does the graph of y=e^x undergoes to get to y=1/(e^x +2) ? I have plotted both graphs but can’t seem to figure what transformations happened after y=1/e^x.
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RDKGames
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(Original post by Janej77)
What sort of transformation does the graph of y=e^x undergoes to get to y=1/(e^x +2) ? I have plotted both graphs but can’t seem to figure what transformations happened after y=1/e^x.
That transformation is not a linear one.
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Janej77
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(Original post by RDKGames)
That transformation is not a linear one.
Does this mean that to plot the graph, it would be easier for me to work out few points on the graph and then plot it? The Cartesian equation I’ve got here is from two parametric equations.
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RDKGames
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(Original post by Janej77)
Does this mean that to plot the graph, it would be easier for me to work out few points on the graph and then plot it? The Cartesian equation I’ve got here is from two parametric equations.
Yeah it would be easier to do that, and some analysis, rather than thinking about the linear transformations.

For instance, as x\rightarrow \infty this equation approaches y=0.

As x\rightarrow -\infty this equation approaches y=\frac{1}{2}.

So the curve has two horizontal asymptotes.
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mqb2766
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(Original post by Janej77)
What sort of transformation does the graph of y=e^x undergoes to get to y=1/(e^x +2) ? I have plotted both graphs but can’t seem to figure what transformations happened after y=1/e^x.
You can sketch e^x+2?
Draw the line y = 1
The curve "y" you want is such that y*(e^x+2) = 1
So if
e^x+2 = 2 then y = 1/2
e^x+2 = 3 then y = 1/3
e^x+2 = 10 then y = 1/10 ...
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Janej77
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Thank you all for your help and your time. I have managed to sketch out the graph correctly.
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