# Can anyone show the solution to this problem?

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x-2py=-3

3x-2y+q=-4

Are simultaneous equations where p and q are constants.

The solution to these simultaneous equations is x=1,y=q. Find the values of p and q.

3x-2y+q=-4

Are simultaneous equations where p and q are constants.

The solution to these simultaneous equations is x=1,y=q. Find the values of p and q.

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#2

(Original post by

x-2py=-3

3x-2y+q=-4

Are simultaneous equations where p and q are constants.

The solution to these simultaneous equations is x=1,y=q. Find the values of p and q.

**Farhan01**)x-2py=-3

3x-2y+q=-4

Are simultaneous equations where p and q are constants.

The solution to these simultaneous equations is x=1,y=q. Find the values of p and q.

3x-2y+q=-4 rearrange this to 3x - 2y = -4 - q

How do we get the same x coefficient in the two equations?

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#3

Replace each 'x' term with just '1' (essentially subbing in x=1) and do the same for the y's (i.e. replace the y's with q's) and then solve for p and q. I don't really know how far you got into this so can't give any more specific advice.

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#4

I think I have a solution:

substitute your x and y values so the equations become

1-2pq=-3

3-2q+q=-4 which then becomes 3-q=-4 when the q values are simplified

You would then solve this to find that q=7 and substitue this value into the other equation.

the other equation would then become 1-14p=-3

14p=4 so that means that p=4/14

substitute your x and y values so the equations become

1-2pq=-3

3-2q+q=-4 which then becomes 3-q=-4 when the q values are simplified

You would then solve this to find that q=7 and substitue this value into the other equation.

the other equation would then become 1-14p=-3

14p=4 so that means that p=4/14

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#5

**Farhan01**)

x-2py=-3

3x-2y+q=-4

Are simultaneous equations where p and q are constants.

The solution to these simultaneous equations is x=1,y=q. Find the values of p and q.

1

reply

(Original post by

I think I have a solution:

substitute your x and y values so the equations become

1-2pq=-3

3-2q+q=-4 which then becomes 3-q=-4 when the q values are simplified

You would then solve this to find that q=7 and substitue this value into the other equation.

the other equation would then become 1-14p=-3

14p=4 so that means that p=4/14

**areeja1510**)I think I have a solution:

substitute your x and y values so the equations become

1-2pq=-3

3-2q+q=-4 which then becomes 3-q=-4 when the q values are simplified

You would then solve this to find that q=7 and substitue this value into the other equation.

the other equation would then become 1-14p=-3

14p=4 so that means that p=4/14

A-Levels are such a pain! Even the simplest problems are twisted :'(

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(Original post by

Replace each 'x' term with just '1' (essentially subbing in x=1) and do the same for the y's (i.e. replace the y's with q's) and then solve for p and q. I don't really know how far you got into this so can't give any more specific advice.

**Fas**)Replace each 'x' term with just '1' (essentially subbing in x=1) and do the same for the y's (i.e. replace the y's with q's) and then solve for p and q. I don't really know how far you got into this so can't give any more specific advice.

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(Original post by

Funny the world's best mathematician is asking help on TSR.

**Turquaz**)Funny the world's best mathematician is asking help on TSR.

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(Original post by

I got q as 7 and p as 2/7. Just wanna be right before I help

**ChrisSharman**)I got q as 7 and p as 2/7. Just wanna be right before I help

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#11

(Original post by

I got the same answers though but the answer in my textbook is p=2 and q=-3

**Farhan01**)I got the same answers though but the answer in my textbook is p=2 and q=-3

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#12

The solution in the book is definitely incorrect because the second equation is only dependent on q and there can only be one point such that (1,q) lies on 3x-2y+q=-4. You can try and experiment by changing the value of q and graphing the equation each time. You will see that the point (1,q) only lies on the line when q=7.

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Thank you all. You guys are right, the answers in my textbook are definitely wrong.

A-Levels are already tough and on top of that, the textbooks aren't reliable. Really feel hopeless :'(

A-Levels are already tough and on top of that, the textbooks aren't reliable. Really feel hopeless :'(

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#14

(Original post by

Thank you all. You guys are right, the answers in my textbook are definitely wrong.

A-Levels are already tough and on top of that, the textbooks aren't reliable. Really feel hopeless :'(

**Farhan01**)Thank you all. You guys are right, the answers in my textbook are definitely wrong.

A-Levels are already tough and on top of that, the textbooks aren't reliable. Really feel hopeless :'(

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(Original post by

Yeah that's why my teacher said the school didn't bother doing an order in for the textbooks cause new spec ones have mistakes and they get fixed afterwards but no point spending money on books with mistakes and having loads of them

**Iahmed512**)Yeah that's why my teacher said the school didn't bother doing an order in for the textbooks cause new spec ones have mistakes and they get fixed afterwards but no point spending money on books with mistakes and having loads of them

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#16

(Original post by

I feel like I wasted my money Moreover I can't even find a single solution bank for the new textbooks on the internet.

**Farhan01**)I feel like I wasted my money Moreover I can't even find a single solution bank for the new textbooks on the internet.

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