geometrical and opitcal isomer exam question pls help

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usernamenew
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Q2.Which one of the following can exhibit both geometrical and optical isomerism?
A (CH3)2C=CHCH(CH3)CH2CH3
B CH3CH2CH=CHCH(CH3)CH2CH3
C (CH3)2C=C(CH2CH3)2
D CH3CH2CH(CH3)CH(CH3)C=CH2

why is the answer b? ive drawn them all out but I still find it hard to see the chiral carbon and geometrical isomerism? how do I draw C
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charco
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(Original post by usernamenew)
Q2.Which one of the following can exhibit both geometrical and optical isomerism?
A (CH3)2C=CHCH(CH3)CH2CH3
B CH3CH2CH=CHCH(CH3)CH2CH3
C (CH3)2C=C(CH2CH3)2
D CH3CH2CH(CH3)CH(CH3)C=CH2

why is the answer b? ive drawn them all out but I still find it hard to see the chiral carbon and geometrical isomerism? how do I draw C
Geometric isomerism requires that each of the carbon atoms of the double bond have different substituents.
Optical isomerism requires that a carbon atom has four different groups attached.
Only B has both.
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usernamenew
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(Original post by charco)
Geometric isomerism requires that each of the carbon atoms of the double bond have different substituents.
Optical isomerism requires that a carbon atom has four different groups attached.
Only B has both.
thanks is the chiral centre on B on
CH3CH2CH=CHCH(CH3)CH2CH3
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charco
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(Original post by usernamenew)
thanks is the chiral centre on B on
CH3CH2CH=CHCH(CH3)CH2CH3
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az2004583
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why is it not A then ? I think it does have a chiral center with it and is also an optical isomer.
Last edited by az2004583; 1 year ago
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charco
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(Original post by az2004583)
why is it not A then ? I think it does have a chiral center with it and is also an optical isomer.
Thread from 2 years ago?

A. (CH3)2C=CHCH(CH3)CH2CH3

does indeed have a chiral carbon (shown above)

But it has no stereoisomers (cis, trans) due to lack of rotation about the double bond as there are two identical groups attached to the first carbon of the double bond.
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az2004583
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(Original post by charco)
Thread from 2 years ago?

A. (CH3)2C=CHCH(CH3)CH2CH3

does indeed have a chiral carbon (shown above)

But it has no stereoisomers (cis, trans) due to lack of rotation about the double bond as there are two identical groups attached to the first carbon of the double bond.
okay yes , Thank you
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