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Further differentiation

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Can someone help me with question 2, I’m not sure where to go from here
On the right hand side, take the factor dy/dx outside a bracket, then rearrange to make dy/dx the subject. (And by the the term 4(dy/dx) on your last line of working should have a minus sign in front of it).
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jack_dvh
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Original post by Hannahkisley
AB8A1AD8-0301-4198-BE92-6E792B21F6DF.jpg.jpeg772E6CD5-B26D-4309-B8B2-A44B02102E7C.jpg.jpeg
Can someone help me with question 2, I’m not sure where to go from here


First of all, on your last line of working, the '+4' should be '-4' (if your last line isn't meant to be erased).
Then just rearrange for dy/dx.

Now, the question asks for a vertical tangent which has a gradient of?

(infinity)

This means dy/dx = infinity, and this is true when you set the denominator equal to zero.

With your new equation, simply rearrange to find y.
:smile:
(edited 5 years ago)

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