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4 Maths Questions (Mechanics)
1)As a lift moves upwards its motion has three stages
Stage 1 - It accelerates uniformly, from rest, at 0.2ms for 8 seconds.
Stage 2 - it then travels at a contsnat speed for 3 seconds.
Stage 3 - It then decelerates uniformly, stopping when it has travelled a further 1 metre.
ai) Find the distance travelled by the lift in Stage 1.
ii) Find the speed of the lift at the end of Stage 1.
iii) Find the total distance travelled by the lift.
b) Find the total time for which the lift is moving.
c) The lift and its passengers have a total mass of 600kg. The lift is supported by a single cable. Find the tension in the cable when the lift is accelerating upward is 0.2
2) A particle moves on a straight line. At time t seconds its acceleration, a ms is given by
a= 20sin4t
a) Intially the particle is at rest. Find an expresssion for the velocity of the particle at time t.
b) Intially the displacement of the particle from the origin is 0.8meteres. Find an expression for the displacement of the particle at time t.
Please, help this is my assignment in need to hand it in by the end of the day.
Help.
I will post the other two questions later please help.
Apparently, these are 2 past paper questions.
Stage 1 - It accelerates uniformly, from rest, at 0.2ms for 8 seconds.
Stage 2 - it then travels at a contsnat speed for 3 seconds.
Stage 3 - It then decelerates uniformly, stopping when it has travelled a further 1 metre.
ai) Find the distance travelled by the lift in Stage 1.
ii) Find the speed of the lift at the end of Stage 1.
iii) Find the total distance travelled by the lift.
b) Find the total time for which the lift is moving.
c) The lift and its passengers have a total mass of 600kg. The lift is supported by a single cable. Find the tension in the cable when the lift is accelerating upward is 0.2
2) A particle moves on a straight line. At time t seconds its acceleration, a ms is given by
a= 20sin4t
a) Intially the particle is at rest. Find an expresssion for the velocity of the particle at time t.
b) Intially the displacement of the particle from the origin is 0.8meteres. Find an expression for the displacement of the particle at time t.
Please, help this is my assignment in need to hand it in by the end of the day.
Help.
I will post the other two questions later please help.
Apparently, these are 2 past paper questions.
Jay Mehta
1)As a lift moves upwards its motion has three stages
Stage 1 - It accelerates uniformly, from rest, at 0.2ms for 8 seconds.
Stage 2 - it then travels at a contsnat speed for 3 seconds.
Stage 3 - It then decelerates uniformly, stopping when it has travelled a further 1 metre.
ai) Find the distance travelled by the lift in Stage 1.
ii) Find the speed of the lift at the end of Stage 1.
iii) Find the total distance travelled by the lift.
b) Find the total time for which the lift is moving.
c) The lift and its passengers have a total mass of 600kg. The lift is supported by a single cable. Find the tension in the cable when the lift is accelerating upward is 0.2
2) A particle moves on a straight line. At time t seconds its acceleration, a ms is given by
a= 20sin4t
a) Intially the particle is at rest. Find an expresssion for the velocity of the particle at time t.
b) Intially the displacement of the particle from the origin is 0.8meteres. Find an expression for the displacement of the particle at time t.
Please, help this is my assignment in need to hand it in by the end of the day.
Help.
I will post the other two questions later please help.
Apparently, these are 2 past paper questions.
Stage 1 - It accelerates uniformly, from rest, at 0.2ms for 8 seconds.
Stage 2 - it then travels at a contsnat speed for 3 seconds.
Stage 3 - It then decelerates uniformly, stopping when it has travelled a further 1 metre.
ai) Find the distance travelled by the lift in Stage 1.
ii) Find the speed of the lift at the end of Stage 1.
iii) Find the total distance travelled by the lift.
b) Find the total time for which the lift is moving.
c) The lift and its passengers have a total mass of 600kg. The lift is supported by a single cable. Find the tension in the cable when the lift is accelerating upward is 0.2
2) A particle moves on a straight line. At time t seconds its acceleration, a ms is given by
a= 20sin4t
a) Intially the particle is at rest. Find an expresssion for the velocity of the particle at time t.
b) Intially the displacement of the particle from the origin is 0.8meteres. Find an expression for the displacement of the particle at time t.
Please, help this is my assignment in need to hand it in by the end of the day.
Help.
I will post the other two questions later please help.
Apparently, these are 2 past paper questions.
1. use the standard equations like v=u+at, v^2=u^2 +2as and so on. you should just be able to plug them in and get the answers.
2. integrate
Jay Mehta
Can you do it please.
i was working it on yesterday for about 2 hours couldn't get any where
i was working it on yesterday for about 2 hours couldn't get any where
no, trust me i have better things to do.
literally just use the motion formulas for the first one, its easy. for c) use F=ma.
for 2, just integrate it once to get velocity and twice to get distance.
As a lift moves upwards its motion has three stages:
Stage 1 - It accelerates uniformly, from rest, at 0.2ms for 8 seconds.
Stage 2 - it then travels at a contsnat speed for 3 seconds.
Stage 3 - It then decelerates uniformly, stopping when it has travelled a further 1 metre.
ai) Find the distance travelled by the lift in Stage 1.
u = 0, a = 0.2, t = 8
s = ut + 1/2at^2
---> s = 1/2 * 0.2 * (8)^2
---> s = 1/2 * 0.2 * 64
---> Distance Travelled (Stage 1) = 6.4m
ii) Find the speed of the lift at the end of Stage 1.
u = 0, a = 0.2, t = 8, s = 6.4
v = u + at
---> v = 0.2*8
---> Speed (End Of Stage 1) = 1.6ms^-1
iii) Find the total distance travelled by the lift.
In stage 2: t = 3, u = 1.6, v = 1.6, a = 0
s = (u+v)/2t
---> s = (3.2)/2 * 3
---> Distance Travelled (Stage 2) = 4.8m
In stage 3: Distance Travelled = 1m
Total Distance Travelled = 6.4 + 4.8 + 1 = 12.2m
b) Find the total time for which the lift is moving.
Stage 1: t = 8
Stage 2: t = 3
Stage 3: u = 1.6, v = 0, s = 1
s = (u+v)/2t
---> 1 = 1.6/2t
---> 1 = 0.8t
---> t = 1.25s
Total Time (Lift Moving) = 8 + 3 + 1.25 = 12.25s
c) The lift and its passengers have a total mass of 600kg. The lift is supported by a single cable. Find the tension in the cable when the lift is accelerating upward is 0.2
F = ma
---> F = 600*0.2
---> Tension (Cable) = 120N
2) A particle moves on a straight line. At time t seconds its acceleration, a ms is given by
a = 20sin4t
a) Intially the particle is at rest. Find an expresssion for the velocity of the particle at time t.
a = 20sin4t, u = 0, t = t
v = u + at
---> v = 0 + (20sin4t)t
---> Velocity Of Particle (At time t) = 20tsin4t
b) Intially the displacement of the particle from the origin is 0.8meteres. Find an expression for the displacement of the particle at time t.
s = (u+v)/2*t + Initial Displacement
---> s = (20tsin4t + 0)/2*t + 0.8
---> s = 20t^2sin4t/2 + 0.8
---> Displacement (Particle) = 10t^2sin4t + 0.8
Stage 1 - It accelerates uniformly, from rest, at 0.2ms for 8 seconds.
Stage 2 - it then travels at a contsnat speed for 3 seconds.
Stage 3 - It then decelerates uniformly, stopping when it has travelled a further 1 metre.
ai) Find the distance travelled by the lift in Stage 1.
u = 0, a = 0.2, t = 8
s = ut + 1/2at^2
---> s = 1/2 * 0.2 * (8)^2
---> s = 1/2 * 0.2 * 64
---> Distance Travelled (Stage 1) = 6.4m
ii) Find the speed of the lift at the end of Stage 1.
u = 0, a = 0.2, t = 8, s = 6.4
v = u + at
---> v = 0.2*8
---> Speed (End Of Stage 1) = 1.6ms^-1
iii) Find the total distance travelled by the lift.
In stage 2: t = 3, u = 1.6, v = 1.6, a = 0
s = (u+v)/2t
---> s = (3.2)/2 * 3
---> Distance Travelled (Stage 2) = 4.8m
In stage 3: Distance Travelled = 1m
Total Distance Travelled = 6.4 + 4.8 + 1 = 12.2m
b) Find the total time for which the lift is moving.
Stage 1: t = 8
Stage 2: t = 3
Stage 3: u = 1.6, v = 0, s = 1
s = (u+v)/2t
---> 1 = 1.6/2t
---> 1 = 0.8t
---> t = 1.25s
Total Time (Lift Moving) = 8 + 3 + 1.25 = 12.25s
c) The lift and its passengers have a total mass of 600kg. The lift is supported by a single cable. Find the tension in the cable when the lift is accelerating upward is 0.2
F = ma
---> F = 600*0.2
---> Tension (Cable) = 120N
2) A particle moves on a straight line. At time t seconds its acceleration, a ms is given by
a = 20sin4t
a) Intially the particle is at rest. Find an expresssion for the velocity of the particle at time t.
a = 20sin4t, u = 0, t = t
v = u + at
---> v = 0 + (20sin4t)t
---> Velocity Of Particle (At time t) = 20tsin4t
b) Intially the displacement of the particle from the origin is 0.8meteres. Find an expression for the displacement of the particle at time t.
s = (u+v)/2*t + Initial Displacement
---> s = (20tsin4t + 0)/2*t + 0.8
---> s = 20t^2sin4t/2 + 0.8
---> Displacement (Particle) = 10t^2sin4t + 0.8
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can someone please explain what principle domain is and why the answer is a not c?Maths
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