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quick math gcse question...

what does dy/dx in differentiation actually mean because I'm so confused.
(edited 5 years ago)
dy/dy doesn't mean anything...? If you mean dy/dx, it just means how is y changing in terms of x.

For example, dy/dx of x^2 = 2x, at the given value of x, the gradient is 2x
(edited 5 years ago)
Original post by aliceaquaspirit
what does dy/dy in differentiation actually mean because I'm so confused.


It means an infinitesimally small change in yy divided by an infinitesimally small change in yy... so the whole thing just evaluates to 1.
hahaha yeah sorry, typo. thanks !!!
Original post by Guarddyyy
dy/dy doesn't mean anything...? If you mean dy/dx, it just means how is y changing in terms of x (e.g. equation of the rate of change of the gradient).

For example, dy/dx of x^2 = 2x, at the given value of x, the gradient is 2x


Careful with the wording - the rate of change of the gradient is d2ydx2\dfrac{d^2 y}{dx^2}, because the gradient itself along the curve is dydx\dfrac{dy}{dx}.
Original post by RDKGames
Careful with the wording - the rate of change of the gradient is d2ydx2\dfrac{d^2 y}{dx^2}, because the gradient itself along the curve is dydx\dfrac{dy}{dx}.


I lose most of my marks in explanation questions :colondollar:

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