# coefficient of x^6

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#1
I'm really confused on how to answer this question as we haven't been taught it but been given it for homework can anyone help

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2 years ago
#2
(Original post by utv)
I'm really confused on how to answer this question as we haven't been taught it but been given it for homework can anyone help

I guess you have been taught about the binomial expansion?
If so, work out which powers will give x^3 and x^6. What is the power of the first term, second term, ... you should be able to do it.

Edit: is a reasonable overview
Last edited by mqb2766; 2 years ago
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#3
I've covered binomial expansion and working out the coficient but not like this. may you help? usually if I want to work out coficient of x^4 in ,(2x-3)^5 you would

do do (2x)^4 × 5choose1 ×-3 then again to work out coficient but it's more confusing
0
2 years ago
#4
(Original post by utv)
I've covered binomial expansion and working out the coficient but not like this. may you help? usually if I want to work out coficient of x^4 in ,(2x-3)^5 you would

do do (2x)^4 × 5choose1 ×-3 then again to work out coficient but it's more confusing
The binomial is generally (a b)^n where in this case
a = x^2
b = -1/2x
n = 6
So what is the first term, second term, and then once you've sharpened your skills do the x^3 term and the x^6 term?
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