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I understand lines 1 to 2, but after that im confused. the question is asking to find the value of N given the equation on the first line. im confused on how the equaitons on line 3 are equal, and why line 4 = 12(n+1) . i get line 5, but i have no idea whats going on in line 6 and where they got those numbers from, are they grouping both of the equations made out of the first one or are they only considering the 5th line? and why do they make them equal to eachother on the 8th line? thanks
https://imgur.com/a/Jh91eJU
https://imgur.com/a/Jh91eJU
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#4
For line 3, you are just rearranging the equation on line 2 to get that summation.
For the 4th line, you understand that the summation can be split into the 2 other summations?
Now the summation for 2n, r=1, and sum of the 12, can be written as (2n)(12) = 24n.
The other summation for n-1, r=1 and sum of the 12, can be written as (n-1)(12) = 12n - 12
now 24n - (12n-12) = 24n - 12n + 12 = 12n + 12 = 12(n+1)
For the 4th line, you understand that the summation can be split into the 2 other summations?
Now the summation for 2n, r=1, and sum of the 12, can be written as (2n)(12) = 24n.
The other summation for n-1, r=1 and sum of the 12, can be written as (n-1)(12) = 12n - 12
now 24n - (12n-12) = 24n - 12n + 12 = 12n + 12 = 12(n+1)
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#5
What it seems like what they are doing, is grouping all of the sum of a constant, and then sum of a variable together. If I could type this up in TSR it would make my life a whole lot easier...
But I hope this makes sense, if not, lemme know.
But I hope this makes sense, if not, lemme know.
Last edited by Guarddyyy; 2 years ago
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(Original post by Guarddyyy)
For line 3, you are just rearranging the equation on line 2 to get that summation.
For the 4th line, you understand that the summation can be split into the 2 other summations?
Now the summation for 2n, r=1, and sum of the 12, can be written as (2n)(12) = 24n.
The other summation for n-1, r=1 and sum of the 12, can be written as (n-1)(12) = 12n - 12
now 24n - (12n-12) = 24n - 12n + 12 = 12n + 12 = 12(n+1)
For line 3, you are just rearranging the equation on line 2 to get that summation.
For the 4th line, you understand that the summation can be split into the 2 other summations?
Now the summation for 2n, r=1, and sum of the 12, can be written as (2n)(12) = 24n.
The other summation for n-1, r=1 and sum of the 12, can be written as (n-1)(12) = 12n - 12
now 24n - (12n-12) = 24n - 12n + 12 = 12n + 12 = 12(n+1)
ah ok i see so whenever theres just a number instead of an R you just multiply that number by the number ontop of the sigma sign?
for the 4th line i see that but i dont get how it translates into the equation on the next line, when its 2r do i just do the standard 1/2n(n+1) and then multiply it by 2? i think i see how the equation comes into place now so thank you
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#7
I'm not 100% sure what you mean by a number instead of r, but for the 4th line (I'm assuming you mean the 2n, r=n and sum 12), it's not in any way connected to line 5 (where it has 2n, r=n and 2r). It seems like the challenge is just breaking down each section by first dealing with the sum of the 12ths then sum of the 2r's.
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#8
(Original post by Gent2324)
I understand lines 1 to 2, but after that im confused. the question is asking to find the value of N given the equation on the first line. im confused on how the equaitons on line 3 are equal, and why line 4 = 12(n+1) . i get line 5, but i have no idea whats going on in line 6 and where they got those numbers from, are they grouping both of the equations made out of the first one or are they only considering the 5th line? and why do they make them equal to eachother on the 8th line? thanks
https://imgur.com/a/Jh91eJU
I understand lines 1 to 2, but after that im confused. the question is asking to find the value of N given the equation on the first line. im confused on how the equaitons on line 3 are equal, and why line 4 = 12(n+1) . i get line 5, but i have no idea whats going on in line 6 and where they got those numbers from, are they grouping both of the equations made out of the first one or are they only considering the 5th line? and why do they make them equal to eachother on the 8th line? thanks
https://imgur.com/a/Jh91eJU
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(Original post by sweetstars)
uhh what is this nonsense? XD what topic is this in further maths? (also is this a-level or gcse?)
uhh what is this nonsense? XD what topic is this in further maths? (also is this a-level or gcse?)
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#14
Not yet, I am about to move on to volumes of revolution, then I think matrices then proof by induction,
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#15
(Original post by Gent2324)
series, chapter 3, it is a challenge question though so its not all on that difficulty. we did it last term but i forgot it and we've started proof by induction now and i needed to revisit series. and yes its a level. do you do series in gcse?
series, chapter 3, it is a challenge question though so its not all on that difficulty. we did it last term but i forgot it and we've started proof by induction now and i needed to revisit series. and yes its a level. do you do series in gcse?
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(Original post by sweetstars)
Thanks for answering. We do it neither in gcse maths or gcse further maths thankfully. I'm already struggling in further maths while everyone whizzes through all those questions. XD Also sorry for commeting something irrelevant, i feel like I'm just unnecessarily filling up your thread.
Thanks for answering. We do it neither in gcse maths or gcse further maths thankfully. I'm already struggling in further maths while everyone whizzes through all those questions. XD Also sorry for commeting something irrelevant, i feel like I'm just unnecessarily filling up your thread.
(Original post by Guarddyyy)
Not yet, I am about to move on to volumes of revolution, then I think matrices then proof by induction,
Not yet, I am about to move on to volumes of revolution, then I think matrices then proof by induction,
matrices is incredibly easy and so is linear transformations, not complicated at all really. roots of polynomials is fine, loci in the argand diagrams are hell

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#17
(Original post by Gent2324)
no worries, its not ridiculously hard it just looks a bit weird when looking at it for the first time (or the 200th if youre me)
we're starting volumes of revolution but our teacher has had to teach us integration and differentiation first, apparently its easy.
matrices is incredibly easy and so is linear transformations, not complicated at all really. roots of polynomials is fine, loci in the argand diagrams are hell
. proof by induction is easy up until you have to rearrange a quadratic or up to quartic into the given equation. it gets pretty confusing with factorials etc..
no worries, its not ridiculously hard it just looks a bit weird when looking at it for the first time (or the 200th if youre me)
we're starting volumes of revolution but our teacher has had to teach us integration and differentiation first, apparently its easy.
matrices is incredibly easy and so is linear transformations, not complicated at all really. roots of polynomials is fine, loci in the argand diagrams are hell

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(Original post by Guarddyyy)
I'm about to begin integrating and differentiating trigonometry (because I'm in A2, but I'm doing AS Further Maths).
I'm about to begin integrating and differentiating trigonometry (because I'm in A2, but I'm doing AS Further Maths).
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#19
(Original post by Gent2324)
what modules are you doing for fm? i was going to do stats and mechanics but ive started to hate applied maths so we're doing decision and further pure 1 instead
what modules are you doing for fm? i was going to do stats and mechanics but ive started to hate applied maths so we're doing decision and further pure 1 instead
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(Original post by Guarddyyy)
Modules?... urm... all I know is I'm doing pure 1, stats 1 and mechanics 1.
Modules?... urm... all I know is I'm doing pure 1, stats 1 and mechanics 1.
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