# Transformations HepWatch

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#1
Describe the sequence of transformations which maps
y=1/x^2to y= 2/(x+3)^2
translation (-3 0) on the axis stretch parallel to the y axis by a scale factor of 2
im not sure
Last edited by jsb00; 1 year ago
0
1 year ago
#2
(Original post by jsb00)
Describe the sequence of transformations which maps
y=1/x^2to y= 2/(x+3)^2
translation (-3 0) on the axis stretch parallel to the y axis by a scale factor of 2
im not sure
Yes, although it would probably be slightly better to say an x-translation or shift by -3 and a (vertical) scaling by 2.
Original function
y = f(x)
Modified function
y = 2*f(x+3)
1
1 year ago
#3
what level of study is this? a level maths or fm?
0
#4
(Original post by Gent2324)
what level of study is this? a level maths or fm?
a level maths
0
1 year ago
#5
(Original post by jsb00)
a level maths
are you doing edexcel? if so what topic and chapter?
0
#6
(Original post by Gent2324)
are you doing edexcel? if so what topic and chapter?
yep I'm with edexcel
but this isn't from the book
we get these questions set by teachers
0
1 year ago
#7
(Original post by jsb00)
yep I'm with edexcel
but this isn't from the book
we get these questions set by teachers
yes but what like chapter is this in the textbook where you learn about it, are you in year 2?
0
#8
(Original post by Gent2324)
yes but what like chapter is this in the textbook where you learn about it, are you in year 2?
Chapter 17 Alegbra and Fractions
Yeah im in Y2
0
#9
(Original post by mqb2766)
Yes, although it would probably be slightly better to say an x-translation or shift by -3 and a (vertical) scaling by 2.
Original function
y = f(x)
Modified function
y = 2*f(x+3)
Can you help me with this plz
f(x) = 3x-1
Find the values of x for which
f^-1 (x) = 5/f(x)
if 5/3x-1
0 = 5/3x-1
3x-1=5
6=3x
x=2
Is this right?
0
1 year ago
#10
(Original post by jsb00)
Can you help me with this plz
f(x) = 3x-1
Find the values of x for which
f^-1 (x) = 5/f(x)
if 5/3x-1
0 = 5/3x-1
3x-1=5
6=3x
x=2
Is this right?
When
y = f(x) = 3x-1
* You find the inverse by finding x in tems of y.
* Then substitute y for x to get f^(-1)(x).
* Then equate to 5/f(x) and solve.
I don't think this is what you did?
0
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