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Water of crystallization

On heating 7.0g of fresh sample of Y to constant mass, 2.80g was lost in form of water calculate the number of molecule of water of crystallization in 1mol of Y
Reply 1
Avatar for Akpojiyovwi
Akpojiyovwi
OP
2
On heating 7.0g of fresh sample of Y to constant mass, 2.80g was lost in form of water calculate the number of molecule of water of crystallization in 1mol of Y
Im rusty on these questions but i think its 1 mol of water so 6.02x10^23 molecules.

Can anyone confirm this please?
(edited 5 years ago)
Original post by Akpojiyovwi
On heating 7.0g of fresh sample of Y to constant mass, 2.80g was lost in form of water calculate the number of molecule of water of crystallization in 1mol of Y


Mol of compound = (7.0g - 2.80g)/Mr
Mol of water = 2.80/18

Get ratio
Reply 4
Avatar for Maker
Maker
20
Its not possible to answer the question with the info provided. You need to know the RMM of Y.

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