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Roots of Quadratic Functions

Alexia and Michaela were both trying to solve a quadratic equation of the form x^2 + bx + c = 0

Unfortunately, Alexia misread the value of b and found that the solutions were 6 and 1

Michaela misread the value of c and found that the solutions were 4 and 1

What were the correct solutions


Can someone point me in the right direction, as I'm completely stuck.
Original post by Harry-Pikesley
Alexia and Michaela were both trying to solve a quadratic equation of the form x^2 + bx + c = 0

Unfortunately, Alexia misread the value of b and found that the solutions were 6 and 1

Michaela misread the value of c and found that the solutions were 4 and 1

What were the correct solutions


Can someone point me in the right direction, as I'm completely stuck.


Alexia misread the value of bb, so she got the cc value right. From the roots she got, we can say that 6×1=c6 \times 1 = c straight away by considering the fact that the roots multiply to make the constant term.

Take a similar approach to determine the value of bb from Michaela's mistake.
Original post by RDKGames
Alexia misread the value of bb, so she got the cc value right. From the roots she got, we can say that 6×1=c6 \times 1 = c straight away by considering the fact that the roots multiply to make the constant term.

Take a similar approach to determine the value of bb from Michaela's mistake.

Thanks for the help.

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