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Im struggling with a maths question

Prove that the sum of three consecutive numbers is always a multiple of 3.
How can you algebraically represent 3 consecutive numbers? I’ll give you a tip and say that the first of the 3 consecutive numbers can be listed as ‘n’.
let n be the a number.n 1 is the next number after that.n 2 is the next number after that.They are consecutivethe sum of three consecutive numbers=n n 1 n 2=3n 3factorsied= 3(n 1)any number times by 3 is a multiple of three!Your welcome :wink:
Original post by hasnat614
let n be the a number.n 1 is the next number after that.n 2 is the next number after that.They are consecutivethe sum of three consecutive numbers=n n 1 n 2=3n 3factorsied= 3(n 1)any number times by 3 is a multiple of three!Your welcome :wink:

Please don’t provide full solutions. Try and guide them so that they can figure out the answer largely by themselves. By providing the full solution, they don’t learn.
Original post by WhatIsLife1
Please don’t provide full solutions. Try and guide them so that they can figure out the answer largely by themselves. By providing the full solution, they don’t learn.

Oops sorry, you're right. We need more people like you :smile:

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