Jademorgan1
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#1
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#1
Anyone know how to answer this type of question

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srasgeref
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#2
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#2
just equal both equations and solve using logs

4^3x = 4^x+6
3x log4(4) = x+6 log4(4)
3x = x+6
x = 3
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the bear
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#3
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#3
you need to solve equations....

a) 43x = 4x + 6

b) 4x = 2x + 1

etc
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Justvisited
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#4
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(Original post by srasgeref)
just equal both equations and solve using logs

4^3x = 4^x+6
3x log4(4) = x+6 log4(4)
3x = x+6
x = 3
Um, you don't need to use logs, or even to have ever heard of logs
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JackMac2904
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#5
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You can manipulate the exponents so the base is the same on both sides and then equate the exponents, simply solve from there.
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Jademorgan1
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#6
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Thanks everyone
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