Hess Law helpWatch

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#1
Can someone please explain part b to me
0
1 year ago
#2
For each equation construct a Hess's Law 'triangle'. You have the enthaplies of formation for the reactants and products in each case, so write the (balanced) elements below each equation.
Use Hess's Law to work out the enthalpy of combustion via the enthalpies of formation for the reactants and products.
0
1 year ago
#3
(Original post by jhuk)
Can someone please explain part b to me
Write out the equation for enthalpy of combustion of each compound.

Use

(sum of) formation enthalpy of products - (sum of) formation enthalpy of reactant = enthalpy of reaction.
0
#4
I dont understand how to construct the triangle, I have balanced all the equations
0
1 year ago
#5
(Original post by jhuk)
I dont understand how to construct the triangle, I have balanced all the equations
You construct like the example.

(You should probably include the state symbols, unlike my example!)
1
#6
Thank you
0
1 year ago
#7
(Original post by jhuk)
Thank you
You're welcome!

Hopefully when you did the Hess's triangle for hydrogen you noticed a relationship;
A relationship between the enthalpy of combustion and the enthalpy of formation of water.
Why is that relationship there? Because hydrogen (and the oxygen required in combustion) are elements, so their enthalpy of formation is zero.
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