Issac Physcis

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Kimberley_99
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#1
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#1
The planet Mogg is completely spherical, with radius 2.3×106m Calculate the gravitational field strength at a height of 100km above the surface of the planet. Use the information given in question F5.6 and give your answer to 2 significant figures.

(F5.6 --At a distance of 1.0×107m from the centre of planet Mogg, the gravitational field strength due to Mogg is 2.1Nkg−1. Calculate the gravitational field strength at a distance of 5.0×107m)
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Sinnoh
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#2
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#2
Solve to find the mass then just plug it into the formula
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username3249896
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#3
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You can also use proportionality

g=GM/r^2
since M is constant and G is constant,
g is inversely proportional to r^2
so g1r12=g2r22
here g1 = 2.1Nkg−1 and r1=1.0×107m
g2 = ?, r2= 100 x103 + 2.3×106
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Kimberley_99
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Thank You
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Kimberley_99
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#5
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(Original post by BobbJo)
You can also use proportionality

g=GM/r^2
since M is constant and G is constant,
g is inversely proportional to r^2
so g1r12=g2r22
here g1 = 2.1Nkg−1 and r1=1.0×107m
g2 = ?, r2= 100 x103 + 2.3×106

Thank You
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Kimberley_99
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#6
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#6
How would you use the information in questions F5.6 and F5.7, calculate the gravitational field strength due to planet Mogg at a distance of 3.0x10^6 m from the centre?

F5.7 (The planet Mogg is completely spherical, with radius 2.3×106m Calculate the gravitational field strength at a height of 100km above the surface of the planet. Use the information given in question F5.6 and give your answer to 2 significant figures.

(F5.6 --At a distance of 1.0×107m from the centre of planet Mogg, the gravitational field strength due to Mogg is 2.1Nkg−1. Calculate the gravitational field strength at a distance of 5.0×107m)
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Kimberley_99
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#7
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#7
(Original post by BobbJo)
You can also use proportionality

g=GM/r^2
since M is constant and G is constant,
g is inversely proportional to r^2
so g1r12=g2r22
here g1 = 2.1Nkg−1 and r1=1.0×107m
g2 = ?, r2= 100 x103 + 2.3×106
Thank you
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