# physics question

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#1
I'm not sure how to start answering this question. I think I need to use the formula to find heat energy transferred but I think I need to do something before that. can you please help or advise me ?

A household radiator has an inlet temperature of 67.4*oC and an outlet temperature of 43.4*oC. The water flows through the radiator at a steady rate of 1×10-5*m3*s-1*and the radiator has reached a steady temperature. Given that the density of water is 1000 kg m-3*and its specific heat capacity is 4200 J kg-1*K-1, calculate the rate of heat loss (in W or J s-1) from the radiator.*

Thank you
1
2 years ago
#2
Rate of heat loss = Mass flow rate x specific heat capacity x Change in temperature

First step is to convert that volume flow rate to mass flow rate using the density
2
#3
(Original post by BobbJo)
Rate of heat loss = Mass flow rate x specific heat capacity x Change in temperature

First step is to convert that volume flow rate to mass flow rate using the density
thanks
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