The Student Room Group

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Reply 1
g dm^-3 isn't a concentration! :confused:
mik1a
g dm^-3 isn't a concentration! :confused:

I copied it from a worksheet.
If it helps, the answer is 1.755gdm-3
Reply 3
mik1a
g dm^-3 isn't a concentration! :confused:

It is. It's not as "clean" as moldm^-3, but it is mass/volume. Think of it as the "density" of a solute in a solution, and therefore a concentration.
Reply 4
1)work out the moles of Agno3 = conc. * (volume/1000)
2)equation for reaction gives the number of moles of NaCl
3) concentration of NaCl=moles NaCl/volume(you might need to divide the vol by 1000 to get in dm^-3)
try that?
I still don't understand. Can someone show me the workings?
Reply 6
Widowmaker
I still don't understand. Can someone show me the workings?

do you know the equation for the reaction ie
Nacl + Agno3--->
if u no that then perhaps i can help alittle better
littleone
do you know the equation for the reaction ie
Nacl + Agno3--->
if u no that then perhaps i can help alittle better

Yes, it's
NaCl + AgNO3 --> NaNO3 + AgCl
Chemistboy are you there?
Reply 9
i got 17.55. let me try agin
littleone
i got 17.55. let me try agin

The answer says 1.755gdm-3. I really don't get this one question.
Reply 11
Widowmaker
10 cm3 of a solution of NaCl react with 15 cm3 of 0.02 M silver nitrate solution. What is the concentration of the NaCl solution in g dm-3?


i think maybe the answer is wrong...
if you look at the equation, it is a 1:1 ratio
which means the number of moles of AgNO3 equals that of NaCl
then i guess you'd re arrange conc=moles/volume to get the number of moles
then use that anser in the same equation to get a concentraion
and i reaaly dont get 480 for that
is this what you did?
sozzy i havent been of much help :frown:
littleone
i think maybe the answer is wrong...
if you look at the equation, it is a 1:1 ratio
which means the number of moles of AgNO3 equals that of NaCl
then i guess you'd re arrange conc=moles/volume to get the number of moles
then use that anser in the same equation to get a concentraion
and i reaaly dont get 480 for that
is this what you did?
sozzy i havent been of much help :frown:

No the answer is 1.755gdm-3
I typed the wrong one.
Reply 13
heres wat i did to get 17.55 maybe u can see where ive gone wrong
1:1 ratio
moles AgNO3= concentration * Volume
this equals the moles of NaCl =0.3

then into moles=mass/RelativeFormulaMass
ie.
0.3=mass/58.5
mass=17.55
It's okay, i've worked it out.
Reply 15
moles=0.02*15
Reply 16
Widowmaker
It's okay, i've worked it out.

how? well done btw!
littleone
how? well done btw!


Using the formula; no of moles = volume (cm3*moles)/1000

No of moles of AgNO3 = (15*0.02)/1000
No of moles of NaCl = (10*x)/1000

10x = 15*0.02
10x = 0.3
x = 0.03

No of moles = mass/molar mass

Mass (gdm-3) = No of moles*molar mass = 0.03*58.5 = 1.755gdm-3
hihihihi
I thought you had to convert to dm^3

By dividing by 1000 you are doing that.
Reply 19
Widowmaker
By dividing by 1000 you are doing that.

yeah I was replying to littleon, nm.