# Help with polynomials!

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Thread starter 1 year ago
#1
Can someone help me with this question please??

For (i) I got f(x) = (x-a)(x-3)^2
For (ii) I got a=2 and a=1.

I'm stuck on (iii)

(The question is in the post below)
Last edited by Fazzy_77; 1 year ago
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Thread starter 1 year ago
#2
Here's the question:

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1 year ago
#3
iii) just do the same as ii).... (1 - a)(1 - 3)2 = a2 -10a + 12
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Thread starter 1 year ago
#4
(Original post by the bear)
iii) just do the same as ii).... (1 - a)(1 - 3)2 = a2 -10a + 12
So was my answer right for ii? Also, I don't understand the graphing part of the question.
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1 year ago
#5
(Original post by Fazzy_77)
So was my answer right for ii? Also, I don't understand the graphing part of the question.
yes it was right.

you just have to draw the cubic graphs with the repeated root at 3 and the other root at your value of a.
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Thread starter 1 year ago
#6
(Original post by the bear)
yes it was right.

you just have to draw the cubic graphs with the repeated root at 3 and the other root at your value of a.
Thank you!
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1 year ago
#7
(Original post by begbie68)
Your answer to part (ii) is incorrect.
No, it isn't.
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