Ripple voltage

Suggest, with reasons, a value for capacitance if the output p.d is not to vary by more than 1% when a current of 200mA is drawn from the rectified output.
[Input to rectifier is 56V rms alternating voltage, frequency 200Hz]
[Rectification is full-wave]

I tried the equation
V=V0(1-e^(-t/RC))
but no value of R is given?
I only reach t/RC=ln100
trying R=V/I with the given 200mA is wrong too.

I think the question is about steady state filtering
https://www.radio-electronics.com/info/circuits/diode-rectifier/rectifier-filtering-smoothing-capacitor-circuits.php
rather than the transient (dc) charging V=V0(1-e^(-t/RC)).

Thank you. Does the discharging equation apply to the part where the capacitor discharges in the circuit?



I tried using the equation

Vripple = I/2fC

obtaining C = 8.9 x 10^-4 F



but the answer is 6.3 x 10^-4 F.



This is off by a factor of sqrt 2 but I cannot see where this comes from? Is 200mA the peak current? How can we tell?

is the sqrt(2) because of the rms 56v, does it need peak?