# A level vectors HELP!!!

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#1
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#2
(Original post by G_ogh)
These are the questions
0
2 years ago
#3
For:

10a) use the vector equation of a line r = a + μb

where a is a fixed point, b is the position vector (AB = b - a), r is the general point in the line and μ is a scalar (note that I use μ instead of lambda as it is indicated in the next question.

10b) You now two equations that have an equal r such that you should make an attempt to see if they do intersect via simultaneous equations. If LHS does not = RHS when you have defined scalars then they do not.

10c) Use the formula cosθ = (b.d)/mod(b)*mod(d)

where b and d are the direction vectors of the two lines, not that mod is modular signs indicating it cannot be negative.

11) intersections
Step 1: Make both equations equal to each other
Step 2: Simplify
Step 3: Create 3 linear simultaneous equations such that you solve two, and the third equation you test to see if the defined scalars equate LHS = RHS.
Step 4: Substitute your value of s or t to state a position vector of their point of intersection.

Hope this helps massively Last edited by delporto8; 2 years ago
1
2 years ago
#4
is this still needed for ordinary A level maths ?

Notnek
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2 years ago
#5
(Original post by delporto8)
11) intersections
Step 1: Make both equations equal to each other
I totally get what you mean by this, but really, how do we make equations equal to each other?

create linear equations in X,Y & Z and solve simultaneously for s and t.
You'll only need 2 of these three equations to find s & t
and for intersection, these values need to be consistent in the 3rd eqn.
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2 years ago
#6
(Original post by the bear)
is this still needed for ordinary A level maths ?

Notnek
No, the vector equation of a line / dot product etc. have been moved to further maths so I'm guessing the OP is a further maths student.
1
2 years ago
#7
(Original post by Notnek)
No, the vector equation of a line / dot product etc. have been moved to further maths so I'm guessing the OP is a further maths student.
that was my impression thanks Notters
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#8
(Original post by delporto8)
For:

10a) use the vector equation of a line r = a + μb

where a is a fixed point, b is the position vector (AB = b - a), r is the general point in the line and μ is a scalar (note that I use μ instead of lambda as it is indicated in the next question.

10b) You now two equations that have an equal r such that you should make an attempt to see if they do intersect via simultaneous equations. If LHS does not = RHS when you have defined scalars then they do not.

10c) Use the formula cosθ = (b.d)/mod(b)*mod(d)

where b and d are the direction vectors of the two lines, not that mod is modular signs indicating it cannot be negative.

11) intersections
Step 1: Make both equations equal to each other
Step 2: Simplify
Step 3: Create 3 linear simultaneous equations such that you solve two, and the third equation you test to see if the defined scalars equate LHS = RHS.
Step 4: Substitute your value of s or t to state a position vector of their point of intersection.

Hope this helps massively Thank you but is it possible if you could tell me the actual answers because vectors are by far my weakest topic 😭
0
2 years ago
#9
(Original post by G_ogh)
Thank you but is it possible if you could tell me the actual answers because vectors are by far my weakest topic 😭
*sharp intake of breath*
1
2 years ago
#10
(Original post by G_ogh)
Thank you but is it possible if you could tell me the actual answers because vectors are by far my weakest topic 😭
And with that attitude they'll remain so...
1
#11
(Original post by begbie68)
*sharp intake of breath*
Can you explain b to me please sorry for asking you to do ALL the questions my bad lol
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2 years ago
#12
for part b) because we have 2 dimensional vectors the only way for the lines not to intersect is if they are parallel....
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2 years ago
#13
(Original post by G_ogh)
Thank you but is it possible if you could tell me the actual answers because vectors are by far my weakest topic 😭
Are you doing further maths A Level?
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2 years ago
#14
any 2 lines in 3D will have at some point 2 of their coords being the same

think about looking up at the sky and seeing aeroplane vapour trails which appear to intersect, but one is way higher than the other.

so, from the vector line eqns, always we can find a pair of coords which will be the same, for some value of s & t (in this case)

so we should be able to equate any 2 pairs of eqns for ordinates

eg
2 lines are :
l1: r = (3i - 2j +k) + p(i + j + k) ; l2 : r = (i + j -2k) + q(2i - j + k)

then think about the 3 eqns for each ordinate

X: 3 + p = 1 + 2q
Y: -2 + p = 1 - q
Z: 1 + p = -2 + q

Choose any 2 of these eqns to solve for p,q

Then, if the 2 lines actually intersect, these values for p,q will be consistent in the 3rd eqn which you've not yet used.

Then, if they do intersect, the pt of intersection will be found when you subst the value(s) of p,q back into their respective line eqns.

In this example I'm using i'd personally use the Y,Z eqns to eliminate q quite easily to give -1 + 2p = -1 , then p = 0, q = 3

sub these back into X-eqn gives 3 + (0) = 1 + 2(-3) which is not true, so the 2 lines do not meet.

You can always use geogebra to check your answers & to see what's happening.
good luck.
0
2 years ago
#15
(Original post by begbie68)
I totally get what you mean by this, but really, how do we make equations equal to each other?

create linear equations in X,Y & Z and solve simultaneously for s and t.
You'll only need 2 of these three equations to find s & t
and for intersection, these values need to be consistent in the 3rd eqn.
So for 3 linear simultaneous equations, you create equations for X, Y and Z as you mentioned. You solve only two equations get two values for s and t. Then the third equation you use to test to see if LHS = RHS. If they do, then they intersect, if not then they are skew.
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