username4010226
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Close to the Himalayas at sea level the following readings for air were taken,
• temperature = 27°C,
• density = 1.2 kgm–3
,
• pressure = 1.0 × 105 Pa.
At the top of Mount Everest the air is at a temperature of –23°C and pressure of 3.3 × 104 Pa.
(a) What is the volume of 1 kg of air at sea level? [0.83 m3
]
(b) What is the volume of the same mass of air at the top of Mount Everest? [2.1 m3
]
(c) What is the density of air at the top of Mount Everest? [0.48 kgm–3
]

answers in []
need help with part b and c
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TSR Jessica
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Sorry you've not had any responses about this. Are you sure you've posted in the right place? Here's a link to our subject forum which should help get you more responses if you post there.
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marinade
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For part b you need to use your Ideal Gas equation.

The volume of gas at sea level is 0.83 m-3 which corresponds to 1 kg.

\frac{p_1V_1}{T_1} = \frac{p_2V_2}{T_2}

I called V1 the volume for air for Everest and and the 2 suffix for my ground level variables.

Rearranging for V1 you get


v_1 = (\frac{273-23}{300}) (\frac{p_2}{p_1}) 0.833  m^3

where the units of Kelvin have cancelled. I find it easier to deal in nice fractions, so for my final answer for (b) I can see I have combined two fractions times the pressures (where Pa) cancel, giving the correct answer.

Once you have got the correct answer for (b), the answer for (c) uses the same method as (a) and ICBST \rho = 0.48 kg m-3 to two significant figures.
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