Oxidation number of N in HNO3 Watch

shenzys
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#1
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#1
??? Can anyone helkp as to how they got the answer +5? I thought it would be -5.
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cpchem
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#2
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#2
3 oxygens at -2 each, one hydrogen (+1), so N must be +5 to sum to zero.
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shenzys
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#3
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#3
But the 3 oxygens are -6, plus the 1 from the hydrogen would have to make the N -5, not +5???
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username153949
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#4
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H = +1
O x 3 = -2 x 3
= -6
net charge on molecule = 0

So +1 -6 +N = 0
=> N = 0+6-1
= +5
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shenzys
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#5
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#5
Oh wait I get it. Thanks!
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TomandJerry09
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#6
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(Original post by billykwok)
H = +1
O x 3 = -2 x 3
= -6
net charge on molecule = 0

So +1 -6 +N = 0
=> N = 0+6-1
= +5

Bilbo - geek
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Sakshit Sharma
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#7
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Considered N=x and oxidation number of H is 1. Oxidation number of O is -2 but there is O3 so -2*3=6.x 1-6=0x-5=0x=5.
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Pigster
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#8
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#8
Wow. Over forty thousand views for such a boring thread with only (up until now) five posts.

Way to go Sak****, you've found an over nine year old thread and added to the conversation. I bet shenzys will sleep easy tonight knowing his question has been answered (not for the first time, that honour must go to billykwok also over nine years ago).

I wonder what shenzys will be up to now? Certainly not working out oxidation states of nitrogen, I'll bet.
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Vinay123567890
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#9
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#9
But nitrogen has no d orbital so how it can expand and get oxidation state 5
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BTAnonymous
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#10
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#10
(Original post by Vinay123567890)
But nitrogen has no d orbital so how it can expand and get oxidation state 5
don't post on a 10 year thread buddy.
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Swati Maste
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#11
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It cannot be -5 because oxygen is more electronegative than nitrogen.. So here nitrogen exhibits positive oxidation state
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