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IB Maths HL portfolio - Elevator
Hi,
so.. i've just been set this maths portfolio and i dont get it! It's seems to be more physics and i never understood physics
preferably anyone else doing IB and this portfolio is needed to help, but i'll post the question and see if you can help. it doesn't seem that hard, except that i dont understand what to do.
---
the formula y=2.5t^3 - 15t^2, represents the position of the elevator, y, measured in meters (y=0 represents ground level) and t represents time measured in minutes (t=0 is the starting time). We know that the trip up and down the shaft, ignoring time spent at the foot of the shaft, is approximately six minutes and that the depth of the shaft is no more than 100 meters.
Use suitable computer software to visualize the motion of the elevator in the shfat. Create a table of values for the position of the elevator for t=0,1,2,3,4,5,6 minutes
1. Use these functions to:
(a) interpret the original vertical line motion simulation
(b) explain the meaning of the negative, positive, and zero values of the velocity graph
(c) explain the relationship between velocity and acceleration in the intervals when the elevator speeds up, slows down and is at rest
(d) evaluate the usefullness and identify the problems of the model in the given situation
Creating your own model
2. List the specifications for a redesign of the freight elevator model.
3. Hence, create a model fo your own
4. Explain how your model addresses the problems of the given model and satisfies the specifications of a well-functionoing elevator for th mining company.
5. Explain how your model may be modified to be useful in other situations
--
Of course, im not asking to do it all for me
, but i do need help !
Thanks
so.. i've just been set this maths portfolio and i dont get it! It's seems to be more physics and i never understood physics
preferably anyone else doing IB and this portfolio is needed to help, but i'll post the question and see if you can help. it doesn't seem that hard, except that i dont understand what to do.
---
the formula y=2.5t^3 - 15t^2, represents the position of the elevator, y, measured in meters (y=0 represents ground level) and t represents time measured in minutes (t=0 is the starting time). We know that the trip up and down the shaft, ignoring time spent at the foot of the shaft, is approximately six minutes and that the depth of the shaft is no more than 100 meters.
Use suitable computer software to visualize the motion of the elevator in the shfat. Create a table of values for the position of the elevator for t=0,1,2,3,4,5,6 minutes
1. Use these functions to:
(a) interpret the original vertical line motion simulation
(b) explain the meaning of the negative, positive, and zero values of the velocity graph
(c) explain the relationship between velocity and acceleration in the intervals when the elevator speeds up, slows down and is at rest
(d) evaluate the usefullness and identify the problems of the model in the given situation
Creating your own model
2. List the specifications for a redesign of the freight elevator model.
3. Hence, create a model fo your own
4. Explain how your model addresses the problems of the given model and satisfies the specifications of a well-functionoing elevator for th mining company.
5. Explain how your model may be modified to be useful in other situations
--
Of course, im not asking to do it all for me
, but i do need help !Thanks
Scroll to see replies
Hi,
so.. i've just been set this maths portfolio and i dont get it! It's seems to be more physics and i never understood physics
preferably anyone else doing IB and this portfolio is needed to help, but i'll post the question and see if you can help. it doesn't seem that hard, except that i dont understand what to do.
---
the formula y=2.5t^3 - 15t^2, represents the position of the elevator, y, measured in meters (y=0 represents ground level) and t represents time measured in minutes (t=0 is the starting time). We know that the trip up and down the shaft, ignoring time spent at the foot of the shaft, is approximately six minutes and that the depth of the shaft is no more than 100 meters.
Use suitable computer software to visualize the motion of the elevator in the shfat. Create a table of values for the position of the elevator for t=0,1,2,3,4,5,6 minutes
1. Use these functions to:
(a) interpret the original vertical line motion simulation
(b) explain the meaning of the negative, positive, and zero values of the velocity graph
(c) explain the relationship between velocity and acceleration in the intervals when the elevator speeds up, slows down and is at rest
(d) evaluate the usefullness and identify the problems of the model in the given situation
Creating your own model
2. List the specifications for a redesign of the freight elevator model.
3. Hence, create a model fo your own
4. Explain how your model addresses the problems of the given model and satisfies the specifications of a well-functionoing elevator for th mining company.
5. Explain how your model may be modified to be useful in other situations
--
Of course, im not asking to do it all for me, but i do need help !
Thanks
so.. i've just been set this maths portfolio and i dont get it! It's seems to be more physics and i never understood physics
preferably anyone else doing IB and this portfolio is needed to help, but i'll post the question and see if you can help. it doesn't seem that hard, except that i dont understand what to do.
---
the formula y=2.5t^3 - 15t^2, represents the position of the elevator, y, measured in meters (y=0 represents ground level) and t represents time measured in minutes (t=0 is the starting time). We know that the trip up and down the shaft, ignoring time spent at the foot of the shaft, is approximately six minutes and that the depth of the shaft is no more than 100 meters.
Use suitable computer software to visualize the motion of the elevator in the shfat. Create a table of values for the position of the elevator for t=0,1,2,3,4,5,6 minutes
1. Use these functions to:
(a) interpret the original vertical line motion simulation
(b) explain the meaning of the negative, positive, and zero values of the velocity graph
(c) explain the relationship between velocity and acceleration in the intervals when the elevator speeds up, slows down and is at rest
(d) evaluate the usefullness and identify the problems of the model in the given situation
Creating your own model
2. List the specifications for a redesign of the freight elevator model.
3. Hence, create a model fo your own
4. Explain how your model addresses the problems of the given model and satisfies the specifications of a well-functionoing elevator for th mining company.
5. Explain how your model may be modified to be useful in other situations
--
Of course, im not asking to do it all for me
, but i do need help !Thanks
ive plotted the graph of the formula and differentiated it to get the velocity and then got the 2nd derivative to get the acceleration; so i got all 3 graphs.
i just dont know where to go from there; i was never good at velocity/acceleration in physics and i dont even know what 1 (a) is asking me to do
i just dont know where to go from there; i was never good at velocity/acceleration in physics and i dont even know what 1 (a) is asking me to do
i plotted the graph of the formula and it goes (0,0) (4,-80) (6,0) basically meaning that at 0 minutes its at ground level, at 4 minutes it reaches the bottom of the mine shaft and then at 6 minutes its at ground level again. The problem is that it then keeps on accelerating which is one thing i can right in 1(d).
the thing is i dont understand what to do for (a) (b) and (c)
the thing is i dont understand what to do for (a) (b) and (c)
jhomie
(a) interpret the original vertical line motion simulation
(b) explain the meaning of the negative, positive, and zero values of the velocity graph
(a) interpret the original vertical line motion simulation
(b) explain the meaning of the negative, positive, and zero values of the velocity graph
a) As I said. instant descent and rise. Not a useful model.
b) It has negative velocity when it's going down, positive velocity when it's going up and zero velocity at the moment when it reaches the lowest point.
ooooh thanks!! the velocity is quadratic, i sort of get it now
what about (c), my teacher said the key is the acceleration, but i just cant see it looking at the graph and i forgot the relationshop between velocity and acceleration
thanks for your help, i have to go now, but ill check back again tomorrow
what about (c), my teacher said the key is the acceleration, but i just cant see it looking at the graph and i forgot the relationshop between velocity and acceleration
thanks for your help, i have to go now, but ill check back again tomorrow
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