Manav5332
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Please help me to understand question 5(b) and 5(di). I don't understand the marking scheme. 9702/22/M/J/18. Thanks
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Eimmanuel
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(Original post by Manav5332)
Please help me to understand question 5(b) and 5(di). I don't understand the marking scheme. 9702/22/M/J/18. Thanks
Upthrust in (b) is using  h \rho g \times A where  \rho is known as density of the oil and A is the cross-sectional area.

As for in (di), you can write N2L:

T - W + U = ma

As upthrust decreases, tension needs to increase to compensate for the decrease of upthrust.

Edit: Did not see the question paper initially.
Last edited by Eimmanuel; 3 years ago
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Manav5332
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(Original post by Eimmanuel)
To help you, you need to "help" us by giving us the question(s).
Haha sorry
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username3249896
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(Original post by Manav5332)
Haha sorry
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b) Calculate upthrust by calculating difference in pressure between upper and lower surface then multiply by x-sectional area of object

d) i) Upthrust decreases. Tension increases. (for equilibrium since constant speed). So the power output = Fv increases
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Manav5332
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(Original post by BobbJo)
b) Calculate upthrust by calculating difference in pressure between upper and lower surface then multiply by x-sectional area of object

d) i) Upthrust decreases. Tension increases. (for equilibrium since constant speed). So the power output = Fv increases
Got it. Thanks
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