Thanks a lot; that really cleared things up. I have another irritating question now though, lol:
At a bank branch the manager has a staff of 12, consisting of 5 men and 7 women, including a Mr Brown and a Mrs Green. He has to make 4 staff of redundant, and he selects 4 staff at random.
i)How many different selections are possible? (12C4 = 495, right?)
ii)How many of these selections include botrh Mr Brown and Mrs Green?
iii)What is the probability that both Mr Brown and Mrs Green are made redundant
The manager then scraps this list and decides to make 2 men redundant and 2 women redundant instead.
iv) How many different selections are possible now? (5C2 x 7C2 i think)
v) Find the probability that both Mr Brown and Mrs Green are made redundant now
I'm stuck on ii), iii) and iv)... I hate stats!