VECTORSWatch

#1
How do i find the unit vector that is perpendicular to u = 2i-j

i did the scalar product and i got 2x-y=0
0
1 week ago
#2
(Original post by man111111)
How do i find the unit vector that is perpendicular to u = 2i-j

i did the scalar product and i got 2x-y=0
Note: There are two unit vectors perpendicular to u.

So, you've performed the dot/scalar product with xi+yj and you now have an equation linking x and y.

Any solution to that will give you a vector perpendicular to u.

Choose any non-zero one, and then scale it to have unit length.
#3
(Original post by ghostwalker)
Note: There are two unit vectors perpendicular to u.

So, you've performed the dot/scalar product with xi+yj and you now have an equation linking x and y.

Any solution to that will give you a vector perpendicular to u.

Choose any non-zero one, and then scale it to have unit length.
0
1 week ago
#4
(Original post by man111111)
How do i find the unit vector that is perpendicular to u = 2i-j

i did the scalar product and i got 2x-y=0
Alternatively, once you understand this approach, all you need to do is take and swap the components around, then switch the sign on one of them.

I.e. , hence the perp vectors are and ... now just normalise them.
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