VECTORS Watch

man111111
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How do i find the unit vector that is perpendicular to u = 2i-j

i did the scalar product and i got 2x-y=0
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ghostwalker
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(Original post by man111111)
How do i find the unit vector that is perpendicular to u = 2i-j

i did the scalar product and i got 2x-y=0
Note: There are two unit vectors perpendicular to u.

So, you've performed the dot/scalar product with xi+yj and you now have an equation linking x and y.

Any solution to that will give you a vector perpendicular to u.

Choose any non-zero one, and then scale it to have unit length.
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man111111
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(Original post by ghostwalker)
Note: There are two unit vectors perpendicular to u.

So, you've performed the dot/scalar product with xi+yj and you now have an equation linking x and y.

Any solution to that will give you a vector perpendicular to u.

Choose any non-zero one, and then scale it to have unit length.
thank you for your help
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RDKGames
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(Original post by man111111)
How do i find the unit vector that is perpendicular to u = 2i-j

i did the scalar product and i got 2x-y=0
Alternatively, once you understand this approach, all you need to do is take \mathbf{u} = 2 \mathbf{i} - \mathbf{j} and swap the components around, then switch the sign on one of them.

I.e. \mathbf{u}' = -\mathbf{i} +2 \mathbf{j}, hence the perp vectors are \mathbf{i} +2 \mathbf{j} and -\mathbf{i} -2 \mathbf{j}... now just normalise them.
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