Biosensors
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foxstudy
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#1
I don't get why glucose oxidase catalyses the reaction between glucose and oxygen to form gluconic acid and hydrogen peroxide. Like what happens to the products afterwards? and why is oxygen involved?
Here is the mark scheme for the biosensors essay on glucose in the blood.
Attachment 793074
Here is the mark scheme for the biosensors essay on glucose in the blood.
Attachment 793074
Last edited by foxstudy; 3 years ago
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#2
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macpatgh-Sheldon
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foxstudy
Hi,
Sorry you have not had an answer yet!
Let me try to help you.
Basically, this reaction is a man-made, in vitro example in order to assay the concentration of glucose in a blood sample - your Q seems to imply that you think it is an in vivo physiological reaction (therefore, NOTHING happens after the reaction, except that you can measure the amount of product [H2O2] in order to work out how much glucose was present in the original pre-reaction sample (of blood)).
You have probs worked out now why this is useful in the diagnosis/monitoring of blood glucose levels IN DIABETES MELLITUS [last point in mark scheme][you will know that in this disease, glucose levels in the blood are high due to lack of sensitivity of insulin receptors [in Type II diabetes] or reduced/absent production of insulin [Type I diabetes].
If you are able to upload/type in the EXACT Q, I can try to give tips on how to work out the points in the answer.
Hi,
Sorry you have not had an answer yet!
Let me try to help you.
Basically, this reaction is a man-made, in vitro example in order to assay the concentration of glucose in a blood sample - your Q seems to imply that you think it is an in vivo physiological reaction (therefore, NOTHING happens after the reaction, except that you can measure the amount of product [H2O2] in order to work out how much glucose was present in the original pre-reaction sample (of blood)).
You have probs worked out now why this is useful in the diagnosis/monitoring of blood glucose levels IN DIABETES MELLITUS [last point in mark scheme][you will know that in this disease, glucose levels in the blood are high due to lack of sensitivity of insulin receptors [in Type II diabetes] or reduced/absent production of insulin [Type I diabetes].
If you are able to upload/type in the EXACT Q, I can try to give tips on how to work out the points in the answer.
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foxstudy
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#5
(Original post by macpatgh-Sheldon)
foxstudy
Hi,
Sorry you have not had an answer yet!
Let me try to help you.
Basically, this reaction is a man-made, in vitro example in order to assay the concentration of glucose in a blood sample - your Q seems to imply that you think it is an in vivo physiological reaction (therefore, NOTHING happens after the reaction, except that you can measure the amount of product [H2O2] in order to work out how much glucose was present in the original pre-reaction sample (of blood)).
You have probs worked out now why this is useful in the diagnosis/monitoring of blood glucose levels IN DIABETES MELLITUS [last point in mark scheme][you will know that in this disease, glucose levels in the blood are high due to lack of sensitivity of insulin receptors [in Type II diabetes] or reduced/absent production of insulin [Type I diabetes].
If you are able to upload/type in the EXACT Q, I can try to give tips on how to work out the points in the answer.
foxstudy
Hi,
Sorry you have not had an answer yet!
Let me try to help you.
Basically, this reaction is a man-made, in vitro example in order to assay the concentration of glucose in a blood sample - your Q seems to imply that you think it is an in vivo physiological reaction (therefore, NOTHING happens after the reaction, except that you can measure the amount of product [H2O2] in order to work out how much glucose was present in the original pre-reaction sample (of blood)).
You have probs worked out now why this is useful in the diagnosis/monitoring of blood glucose levels IN DIABETES MELLITUS [last point in mark scheme][you will know that in this disease, glucose levels in the blood are high due to lack of sensitivity of insulin receptors [in Type II diabetes] or reduced/absent production of insulin [Type I diabetes].
If you are able to upload/type in the EXACT Q, I can try to give tips on how to work out the points in the answer.
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