# vector uderstanding

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Hi,

Im new to vectors and i am confused about the notation. Say you wanted to graphially represent a vector in two dimensional space i get that you can use a directed line segment and we can denote this as PQ with an arrow above. Am i right in saying that the points P and Q have no relevance unless you are dealing with displacement vectors?

Im new to vectors and i am confused about the notation. Say you wanted to graphially represent a vector in two dimensional space i get that you can use a directed line segment and we can denote this as PQ with an arrow above. Am i right in saying that the points P and Q have no relevance unless you are dealing with displacement vectors?

Last edited by hiyatt; 2 years ago

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#2

Since vector PQ (with the arrow on top pointing right) is found by vector q subtract vector p, then positions P & Q would surely have some relevance!

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(Original post by

Since vector PQ (with the arrow on top pointing right) is found by vector q subtract vector p, then positions P & Q would surely have some relevance!

**begbie68**)Since vector PQ (with the arrow on top pointing right) is found by vector q subtract vector p, then positions P & Q would surely have some relevance!

Last edited by hiyatt; 2 years ago

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(Original post by

Hi,

Im new to vectors and i am confused about the notation. Say you wanted to graphially represent a vector in two dimensional space i get that you can use a directed line segment and we can denote this as PQ with an arrow above. Am i right in saying that the points P and Q have no relevance unless you are dealing with displacement vectors?

**hiyatt**)Hi,

Im new to vectors and i am confused about the notation. Say you wanted to graphially represent a vector in two dimensional space i get that you can use a directed line segment and we can denote this as PQ with an arrow above. Am i right in saying that the points P and Q have no relevance unless you are dealing with displacement vectors?

By the way how old are u???

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(Original post by

Here I have tried to answer your question.....

By the way how old are u???

**humble.boy**)Here I have tried to answer your question.....

By the way how old are u???

**b**

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#6

**p**usually denotes position vector of P. ie OP

same for the

**q**vector.

ok, so you're dealing with SUVAT vectors.

Then yes. P & Q are relevant in displacement.

But they can also be used in certain situations with a velocity and/or acceleration equations, since SUVAT eqns can involve all 3 (

**s**,

**v**&

**a**), of course ....

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**humble.boy**)

Here I have tried to answer your question.....

By the way how old are u???

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#8

(Original post by

Thanks, but my question was regarding dropping the endpoints completely and referring to the vector as just

**hiyatt**)Thanks, but my question was regarding dropping the endpoints completely and referring to the vector as just

**b**__b__is completely independent of P & Q, since it's the difference (or journey) between those 2 points from which you derived/calculated the vector

**b**in the first place!

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(Original post by

then that's fine, but I think it's difficult to then say that

**begbie68**)then that's fine, but I think it's difficult to then say that

__b__is completely independent of P & Q, since it's the difference (or journey) between those 2 points from which you derived/calculated the vector**b**in the first place!
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**begbie68**)

then that's fine, but I think it's difficult to then say that

__b__is completely independent of P & Q, since it's the difference (or journey) between those 2 points from which you derived/calculated the vector

**b**in the first place!

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#12

**hiyatt**)

Thanks, but my question was regarding dropping the endpoints completely and referring to the vector as just

**b**

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(Original post by

I did not understand what u said.....

**humble.boy**)I did not understand what u said.....

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#14

(Original post by

joking im actually 20

**hiyatt**)joking im actually 20

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(Original post by

20.....You don't know vector yet???I've heard UK study system is quite difficult.....I'm from india...Here I read vector when I was 12 or13....

**humble.boy**)20.....You don't know vector yet???I've heard UK study system is quite difficult.....I'm from india...Here I read vector when I was 12 or13....

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#16

(Original post by

there's no calculations going on anywhere i have literally opened the first page of my book on vectors lool

**hiyatt**)there's no calculations going on anywhere i have literally opened the first page of my book on vectors lool

As I understand it, you're just starting a maths degree. In my experience, one thing books/lecturers tend to go on about a fair bit (if you're being introduced to vectors at university level) is how/whether what you're doing depends on your choice of coordinates.

In particular, if you have points P, Q, and you define vectors

**p**,

**q**to be OP, OQ, respectively, then your vectors depend on where you've decided to put the origin. But the vector PQ (=

**q - p**) does NOT depend on your choice of origin.

If this is what's going on with you, I have to say that I think they spend too much time/emphasis on this at a time when you're just getting used to the concepts. And so to a large extent I'd say don't worry too much about it - you should be able to pick a lot of it up "by osmosis", and in further lectures you'll probably find you don't need to worry that much (in that you will always be dealing with the form

**v**= (x, y, z) where all you really care about are the values of x, y, and z).

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(Original post by

What's the book?

As I understand it, you're just starting a maths degree. In my experience, one thing books/lecturers tend to go on about a fair bit (if you're being introduced to vectors at university level) is how/whether what you're doing depends on your choice of coordinates.

In particular, if you have points P, Q, and you define vectors

If this is what's going on with you, I have to say that I think they spend too much time/emphasis on this at a time when you're just getting used to the concepts. And so to a large extent I'd say don't worry too much about it - you should be able to pick a lot of it up "by osmosis", and in further lectures you'll probably find you don't need to worry that much (in that you will always be dealing with the form

**DFranklin**)What's the book?

As I understand it, you're just starting a maths degree. In my experience, one thing books/lecturers tend to go on about a fair bit (if you're being introduced to vectors at university level) is how/whether what you're doing depends on your choice of coordinates.

In particular, if you have points P, Q, and you define vectors

**p**,**q**to be OP, OQ, respectively, then your vectors depend on where you've decided to put the origin. But the vector PQ (=**q - p**) does NOT depend on your choice of origin.If this is what's going on with you, I have to say that I think they spend too much time/emphasis on this at a time when you're just getting used to the concepts. And so to a large extent I'd say don't worry too much about it - you should be able to pick a lot of it up "by osmosis", and in further lectures you'll probably find you don't need to worry that much (in that you will always be dealing with the form

**v**= (x, y, z) where all you really care about are the values of x, y, and z).
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**DFranklin**)

What's the book?

As I understand it, you're just starting a maths degree. In my experience, one thing books/lecturers tend to go on about a fair bit (if you're being introduced to vectors at university level) is how/whether what you're doing depends on your choice of coordinates.

In particular, if you have points P, Q, and you define vectors

**p**,

**q**to be OP, OQ, respectively, then your vectors depend on where you've decided to put the origin. But the vector PQ (=

**q - p**) does NOT depend on your choice of origin.

If this is what's going on with you, I have to say that I think they spend too much time/emphasis on this at a time when you're just getting used to the concepts. And so to a large extent I'd say don't worry too much about it - you should be able to pick a lot of it up "by osmosis", and in further lectures you'll probably find you don't need to worry that much (in that you will always be dealing with the form

**v**= (x, y, z) where all you really care about are the values of x, y, and z).

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