# Easy M1 question . EdexcelWatch

Thread starter 4 weeks ago
#1
I’ll put a picture below . My misunderstanding is in part b
I know that in this case , 4g=T
And I understand why that is ( a=0 , F=ma ) but I don’t know how I can know if the speed is 4 ms^-2
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Thread starter 4 weeks ago
#2
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4 weeks ago
#3
The question says ACCRLERATION is 4m^-2 not speed. This may help answer the question.
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Thread starter 4 weeks ago
#4
(Original post by Aaysh)
The question says ACCRLERATION is 4m^-2 not speed. This may help answer the question.
I'm asking about part b , and it says constant speed of 4 ms^-1
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4 weeks ago
#5
(Original post by Leah.J)
I'm asking about part b , and it says constant speed of 4 ms^-1
Newton's first law states that an object will stay stationary or keep moving at a CONSTANT velocity unless a resultant force acts upon the object.

In the question, the speed is given to you so you don't need to worry how and why the speed is constant (obviously resultant force =0). But if you would want to know how such a case would arise in real life, it may be due to air resistance and drag which ALWAYS opposes tbe direction of motion. As an object falls, it reaches terminal velocity which is the max velocity an object can fall at (you probably know this from GCSE Physics).

So it may be that the 4m^-1 is the terminal velocity of the object in the question.
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4 weeks ago
#6
(Original post by Leah.J)
I’ll put a picture below . My misunderstanding is in part b
I know that in this case , 4g=T
And I understand why that is ( a=0 , F=ma ) but I don’t know how I can know if the speed is 4 ms^-2
Constant velocity means it doesn't change as time goes on, so the rate at which it changes is zero ... i.e. acceleration is zero.
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