Current Electricity Watch

MARYAMMARYAM
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Can someone help me with this qs?
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MARYAMMARYAM
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(Original post by MARYAMMARYAM)
Can someone help me with this qs?
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meek-boy
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1st question.....
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meek-boy
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2nd one.....
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MARYAMMARYAM
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but the answer to the 2nd qs is C and not D
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Joinedup
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(Original post by meek-boy)
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2nd one.....
Hi I don't quite agree with this.

The question states the current is reduced from 100 to 20 mA... not by 20mA

the average current over 8s would be 60mA
20+(100-20)/2

giving 480mC
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MARYAMMARYAM
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(Original post by Joinedup)
Hi I don't quite agree with this.

The question states the current is reduced from 100 to 20 mA... not by 20mA

the average current over 8s would be 60mA
20+(100-20)/2

giving 480mC
Yes that is the answer
😊
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meek-boy
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(Original post by Joinedup)
Hi I don't quite agree with this.

The question states the current is reduced from 100 to 20 mA... not by 20mA

the average current over 8s would be 60mA
20+(100-20)/2

giving 480mC
yeah....here we need to take out the average......as it is reducing uniformly......
👍 bro thanks....for pointing out my mistake....
Are u from uk....it is written a level on that book....I don't know whatever it is....😁I'm from india....
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meek-boy
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(Original post by MARYAMMARYAM)
Thankyou so so so so so much❤❤❤❤ but the answer to the 2nd qs is C and not D
yeah....second one is wrong.....Joinedup has solved it correctly......
If u wanna say me thanks.....then is this symbol required too much.....❤......????😬
omit it....
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MARYAMMARYAM
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(Original post by meek-boy)
yeah....here we need to take out the average......as it is reducing uniformly......
👍 bro thanks....for pointing out my mistake....
Are u from uk....it is written a level on that book....I don't know whatever it is....😁I'm from india....
Thanks both of you
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MARYAMMARYAM
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(Original post by meek-boy)
yeah....second one is wrong.....Joinedup has solved it correctly......
If u wanna say me thanks.....then is this symbol required too much.....❤......????😬
omit it....
I was just being polite.....sorry if that is a problem
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