# Vectors helpWatch

Thread starter 3 weeks ago
#1
Hey guys,
I understand how to solve vector problems nearly like this but I've never really seen questions like this before. Could anyone explain the step by step process in terms of how to solve this?

Thanks,
xAikx
0
reply
3 weeks ago
#2
0
reply
Thread starter 3 weeks ago
#3
But this question does not give me an equation of a plane, that's what I'm trying to find out?
0
reply
3 weeks ago
#4
(Original post by xAikx)
But this question does not give me an equation of a plane, that's what I'm trying to find out?
Oops

http://www.songho.ca/math/plane/plane.html
0
reply
3 weeks ago
#5
(Original post by xAikx)
But this question does not give me an equation of a plane, that's what I'm trying to find out?
You should already realise/know that for each plane, there is a unique direction vector which is perpendicular to the plane.
So, this vector can be used to define the plane.

If ai + bj + ck is perpendicular to a plane, then a cartesian equation to the plane is given by ax + by + ck = p

This is what you should already know, as well as why p is important, and how to find the value of p for a particular, or given, plane.
0
reply
Thread starter 3 weeks ago
#6
(Original post by begbie68)
You should already realise/know that for each plane, there is a unique direction vector which is perpendicular to the plane.
So, this vector can be used to define the plane.

If ai + bj + ck is perpendicular to a plane, then a cartesian equation to the plane is given by ax + by + ck = p

This is what you should already know, as well as why p is important, and how to find the value of p for a particular, or given, plane.
And to find p you just use the formula:

r - a = a.n = p ? With n being the vector of xi + yj + zj at point A?
0
reply
3 weeks ago
#7
(Original post by xAikx)
And to find p you just use the formula:

r - a = a.n = p ? With n being the vector of xi + yj + zj at point A?
i think so.

or more simply, just sub an (x,y,z) coord of a point on the plane into the cartesian for the plane ?!
0
reply
X

Write a reply...
Reply
new posts
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### University open days

• Edge Hill University
Undergraduate and Postgraduate - Campus Tour Undergraduate
Mon, 18 Feb '19
• University of the Arts London
MA Innovation Management Open Day Postgraduate
Mon, 18 Feb '19
• University of Roehampton
Department of Media, Culture and Language; School of Education; Business School Undergraduate
Tue, 19 Feb '19

### Poll

Join the discussion

#### Do you give blood?

Yes (50)
9.52%
I used to but I don't now (14)
2.67%
No, but I want to start (189)
36%
No, I am unable to (122)
23.24%
No, I chose not to (150)
28.57%

View All
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.