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Physics Question to do with acceleration

3) Optimus Prime coasts up a hill initially at 11.0 m/s. After
9.3 s he is rolling back down the slope at 7.3 m/s. What is
his acceleration?
g also known as 10
:teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth:v

:cool:This was written by Oxford Maths Gang:cool:
Reply 2
Original post by vicvic38
g also known as 10
:teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth:v

:cool:This was written by Oxford Maths Gang:cool:

That is incorrect, the answer said it was -2m/s^2
Original post by vicvic38
g also known as 10
:teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth::teeth:v

:cool:This was written by Oxford Maths Gang:cool:


have you done suvat?
Original post by steveeem
have you done suvat?

That hasn't come up in my degree yet.

I only know Suzy.

Also I only talk to @protienshake_
acceleration = change in velocity / time. The change in velocity is -7.3m/s(since velocity becomes negative in the opposite direction) - 11m/s / 9.3. So -7.3-11/9.3 = -18.3/9.3 = -2.03 = -2m/s^2.

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