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01sbrals
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The question is:
an engineer is making a circular disc. a model of the disc is drawn as a circle on a set of axes such that it passes through coordinate points P(-1,-1), Q(5,k) and R(7,3). given that angle PRQ is 90 degrees, find the value of k and the area of the disc.
please help!
its six marks.
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Sinnoh
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So the points within the circle would form a right-angled triangle. What circle theorems do you remember that could be relevant?
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01sbrals
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Angle between tangent and radius is 90 degrees?
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CraigFowler
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(Original post by 01sbrals)
The question is:
an engineer is making a circular disc. a model of the disc is drawn as a circle on a set of axes such that it passes through coordinate points P(-1,-1), Q(5,k) and R(7,3). given that angle PRQ is 90 degrees, find the value of k and the area of the disc.
please help!
its six marks.
Look at question. 11 here, very similar

https://www.examsolutions.net/tutori...vel&topic=1297

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CraigFowler
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https://www.examsolutions.net/tutori...vel&topic=1297

Try question 11 very similar

Also if you sketch you will see a right angle PRQ. Gradient of PQ is negative reciprocal of PR. Then find equation for line QR and sub in x value for point Q and solve for y to give value of k
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