# Bond enthalpyWatch

#1
Baso I don’t understand how to find the bond energy reversed
So the question says to calculate the bond energy for I-I
H2 + I-I = 2HI

H-H = +436
H-I = +298

And the energy change is -9KJ/mol
0
6 days ago
#2
Label I-I as y, to simplify it. Then you know (436 + y) -(2 x 298) is equal to -9. Then rearrange the algebra and solve!
0
#3
Thanks you 🙂
0
6 days ago
#4
(Original post by redblue20)
Thanks you 🙂
No problem
0
X

new posts
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### University open days

• University of Roehampton
Department of Media, Culture and Language; School of Education; Business School Undergraduate
Tue, 19 Feb '19
• Edge Hill University
Tue, 19 Feb '19
• University of Kent
Sciences, Social Sciences and Humanities Further education
Tue, 19 Feb '19

### Poll

Join the discussion

#### Do you give blood?

Yes (63)
8.42%
I used to but I don't now (19)
2.54%
No, but I want to start (278)
37.17%
No, I am unable to (181)
24.2%
No, I chose not to (207)
27.67%