Bond enthalpy Watch

redblue20
Badges: 6
Rep:
?
#1
Report Thread starter 6 days ago
#1
Baso I don’t understand how to find the bond energy reversed
So the question says to calculate the bond energy for I-I
H2 + I-I = 2HI

H-H = +436
H-I = +298

And the energy change is -9KJ/mol
Posted on the TSR App. Download from Apple or Google Play
0
reply
Meduser
Badges: 11
Rep:
?
#2
Report 6 days ago
#2
Label I-I as y, to simplify it. Then you know (436 + y) -(2 x 298) is equal to -9. Then rearrange the algebra and solve!
Posted on the TSR App. Download from Apple or Google Play
0
reply
redblue20
Badges: 6
Rep:
?
#3
Report Thread starter 6 days ago
#3
Thanks you 🙂
Posted on the TSR App. Download from Apple or Google Play
0
reply
Meduser
Badges: 11
Rep:
?
#4
Report 6 days ago
#4
(Original post by redblue20)
Thanks you 🙂
No problem
Posted on the TSR App. Download from Apple or Google Play
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • University of Roehampton
    Department of Media, Culture and Language; School of Education; Business School Undergraduate
    Tue, 19 Feb '19
  • Edge Hill University
    Undergraduate and Postgraduate - Campus Tour Undergraduate
    Tue, 19 Feb '19
  • University of Kent
    Sciences, Social Sciences and Humanities Further education
    Tue, 19 Feb '19

Do you give blood?

Yes (63)
8.42%
I used to but I don't now (19)
2.54%
No, but I want to start (278)
37.17%
No, I am unable to (181)
24.2%
No, I chose not to (207)
27.67%

Watched Threads

View All