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Beer Lambert Law and protein concentration

Hi

I have this problem to work out and I just wanted to check if I'm understanding it correctly?

The concentration of a protein stock solution was determined in the following way: A cuvette containing 3mL of 20mM HEPES-NaOH buffer, pH 7.27 was placed in a spectrophotometer and the absorbance was set to zero. Enzyme stock solution (50 microL) in the same buffer was added and the absorbance was recorded as 0.034.

Give the Beer-Lambert equation which relates absorbance with concentration. Show your workings and calculate the concentration of the original enzyme stock solution in microM and mg/mL.

The enzyme Mw =48009.1 Da, E280 = 48.36mM-1cm-1 and the path length is 1cm.

So the beer lambert equation is A = εlc

Is it simply a case of absorbance divided by E280 multiplied by 1:
0.034 / (48.36 x 1) = 0.0007

Do I have to convert the units anywhere?

Thank you!

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