A-level Physics medical imaging question mcq

A radiographer in a hospital directs a parallel beam of X-rays at the leg bone of a patient.
The attenuation (absorption) coefficient of bone is 0.7 cm −1 .
The answers below are given to one significant figure.
What is the percentage intensity of X-rays transmitted through bone of thickness 0.7 cm?

The answer is 40% I have no idea how to get that I've been using the attentuation formula but I don't get 40%
any help would be much appreciated !

fraction absorbed =e^(-0.7x0.7) = 0.6 to 1 sf
fraction transmitted = 0.4
so 40%
Original post by BobbJo

fraction absorbed =e^(-0.7x0.7) = 0.6 to 1 sf
fraction transmitted = 0.4
so 40%

Thank you!! I kept on getting 0.6 you're a star!
If attenuation constant is normally in m^-1 and bone thickness is normally in metres why don’t we convert centimetres to metres? I did 0.7×10 to the -2 for both attenuation and bone thickness and I ended up getting 0.9999. 1-0.9990. = 0%
I am pretty sure 40% is a wrong answer. This is one of mistakes made by OCR paper maker. I = I_0 Exp(-ux) gives the transmitted intensity not the absorbed one.
Original post by newcastletutor
I am pretty sure 40% is a wrong answer. This is one of mistakes made by OCR paper maker. I = I_0 Exp(-ux) gives the transmitted intensity not the absorbed one.

I agree
Original post by Annayg
If attenuation constant is normally in m^-1 and bone thickness is normally in metres why don’t we convert centimetres to metres? I did 0.7×10 to the -2 for both attenuation and bone thickness and I ended up getting 0.9999. 1-0.9990. = 0%

It doesnt really matter as long as you use the same units cm^-1 and cm for thickness as the units cancel and become unitless so as long as both are in the same units of cm then you are fine. I am not sure what you ended up doing.