Sectors and Segments difficult question, need help Watch

OJ Emporium
Badges: 10
Rep:
?
#1
Report Thread starter 4 weeks ago
#1
So I've been trying to attempt this question now, i know for a fact that I'm missing something in the process but i don't understand what it is.

What i did: found the arc length, found the area of the sector and tried to find the other side by using the cos rule which ended up being useless in the end
0
reply
OJ Emporium
Badges: 10
Rep:
?
#2
Report Thread starter 4 weeks ago
#2
The question: https://gyazo.com/72795e483a3929baea3bd80a91f45eb5
0
reply
Notnek
  • Community Assistant
Badges: 20
Rep:
?
#3
Report 4 weeks ago
#3
Part a)? If that's the one you're stuck on then I'm guessing you're stuck finding BD? Consider similar shapes...

EDIT: BD is not required for part a).
Last edited by Notnek; 4 weeks ago
0
reply
OJ Emporium
Badges: 10
Rep:
?
#4
Report Thread starter 4 weeks ago
#4
(Original post by Notnek)
Part a)? If that's the one you're stuck on then I'm guessing you're stuck finding BD? Consider similar shapes...
I mean I can see other shapes in there but i don't see how that helps.
0
reply
OJ Emporium
Badges: 10
Rep:
?
#5
Report Thread starter 4 weeks ago
#5
(Original post by OJ Emporium)
I mean I can see other shapes in there but i don't see how that helps.
As in i don't really know what to do, feel like i've tried everything but im getting confused in the process.
Hell i'm not even sure whether that's actually a right angle in there or something else
0
reply
Notnek
  • Community Assistant
Badges: 20
Rep:
?
#6
Report 4 weeks ago
#6
(Original post by OJ Emporium)
As in i don't really know what to do, feel like i've tried everything but im getting confused in the process.
Hell i'm not even sure whether that's actually a right angle in there or something else
You're told that AC is a tangent to the circle so by a GCSE circle theorem, CAO must be a right-angle.

The aim is to find the shaded area which is the area of triangle CAO minus the area of the sector which I assume you've already found.

So that leaves the area of the triangle which can be found by 1/2 base x height where the base is 12cm. You're left with finding the height which is AC.

I hope I've given you enough to move you along. If you're still stuck, please post all your thoughts and working.

(Ignore what I said about similar shapes above - you don't need it for a))
Last edited by Notnek; 4 weeks ago
0
reply
OJ Emporium
Badges: 10
Rep:
?
#7
Report Thread starter 4 weeks ago
#7
Yea noticed I missed out on that part and made corrections to that error, thanks man.
And dw i got the answer too.
Last edited by OJ Emporium; 4 weeks ago
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • University of Birmingham
    Postgraduate Open Day Postgraduate
    Wed, 20 Mar '19
  • King's College London
    Postgraduate Taught Courses - Arts & Sciences - Strand Campus Postgraduate
    Wed, 20 Mar '19
  • University of East Anglia
    All Departments Open 13:00-17:00. Find out more about our diverse range of subject areas and career progression in the Arts & Humanities, Social Sciences, Medicine & Health Sciences, and the Sciences. Postgraduate
    Wed, 20 Mar '19

Where do you need more help?

Which Uni should I go to? (50)
15.11%
How successful will I become if I take my planned subjects? (28)
8.46%
How happy will I be if I take this career? (63)
19.03%
How do I achieve my dream Uni placement? (51)
15.41%
What should I study to achieve my dream career? (39)
11.78%
How can I be the best version of myself? (100)
30.21%

Watched Threads

View All