Maths help needed! Watch

Juliakinga
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#1
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#1
Workout the values of a and b in the identity.
3ax + 6 - 4 (x+b) = 11x + 14

(its supposed to be a triple = sign, but I don't have the key for it)
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Luqman.ldn
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#2
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Expand the brackets, and equate the like terms.

Collect all the terms with X in the LHS and equate it to the X terms in RHS and do the same with the constants.
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HarryPetes
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6 -4b = 14
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HarryPetes
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#4
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3ax -4x = 11x
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Juliakinga
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#5
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(Original post by Luqman.ldn)
Expand the brackets, and equate the like terms.

Collect all the terms with X in the LHS and equate it to the X terms in RHS and do the same with the constants.
Thanks, but how do I find what a and b equal
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HarryPetes
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just solve those
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HarryPetes
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a =5 and b= -2
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Juliakinga
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#8
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thanks, but I dont get what you mean with those
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HarryPetes
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#9
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message me if your still stuck I'll help you
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Juliakinga
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#10
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(Original post by HarryPetes)
a =5 and b= -2
Thank you, but how do I get there
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HarryPetes
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#11
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because it's an identity, the overall X term on one side is equal to the overall X term on the other side. same goes for the numerical value that is alone.
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HarryPetes
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3ax =15x, so what number times with 3 to equal 15, the answer is a =5
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HarryPetes
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#13
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-4b = 8, so b=-2
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Luqman.ldn
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#14
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3ax+6-4(X+b)= 11x+14

3ax-4x=11x [divide by X ]
3a-4=11
3a=15
a=5

6-4b=14
-4b=8
b=-2
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Juliakinga
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(Original post by HarryPetes)
3ax =15x, so what number times with 3 to equal 15, the answer is a =5
So 15x+6-4b is equal to 15x +14.
so you can take away 6, then divide by 4 and get that b=-2.
Thank you so much for the help
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HarryPetes
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yeah basically, that's one way of seeing it
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Juliakinga
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#17
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(Original post by Luqman.ldn)
3ax+6-4(X+b)= 11x+14

3ax-4x=11x [divide by X ]
3a-4=11
3a=15
a=5

6-4b=14
-4b=8
b=-2
thank you!
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