alevelhelpxoxo
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Can anyone help me with this question?

molecular formulae C8H10 has 4 possible structural isomers that contain a benzene ring. Name them :

1) ethylbenzene
2) 1,2 dimethylbenzene
3) 1,4 dimethylbenzene
4) however I don't get how another isomer is 1,3 dimethylbenzene since CH3 is an activator group ( 2, 4) so how is it possible it ended up in position 3 ??

also part b of this question
- In the presence of concentrated nitric and sulfuric acid, one of the isomers reacts to give one mononitrated compound. Identify which isomer it is and name the compound formed

again I don't understand the basis of trisubstituition because my book has nothing on it any help will be greatly appreciated !
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ThatGuy107
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(Original post by alevelhelpxoxo)
Can anyone help me with this question?

molecular formulae C8H10 has 4 possible structural isomers that contain a benzene ring. Name them :

1) ethylbenzene
2) 1,2 dimethylbenzene
3) 1,4 dimethylbenzene
4) however I don't get how another isomer is 1,3 dimethylbenzene since CH3 is an activator group ( 2, 4) so how is it possible it ended up in position 3 ??

also part b of this question
- In the presence of concentrated nitric and sulfuric acid, one of the isomers reacts to give one mononitrated compound. Identify which isomer it is and name the compound formed

again I don't understand the basis of trisubstituition because my book has nothing on it any help will be greatly appreciated !
Benzene has 3 different structural isomers (1,3 1,4 and 1,2). The electrophile can end up in any of these positions there’s no discrimination between which.

b) conc H2SO4 and conc HNO3 react to produce
NO2 (the nitronium ion) which can then attack
the benzene ring
Hope this helps
Last edited by ThatGuy107; 2 years ago
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