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AQA A-level Biology 7402 - Paper 1 - 6th June 2019

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Original post by Dr..D
But they said *modifies* and it is always associated with golgi


ffsssss
A dimer
Original post by tsunderhi_
Google it, the only dispute would be that its not enough to be a polymer but would aqa really delve in that deep? Because technically it is a polymer as its made from a monomer. Like if its not a polymer then what is it😂
yep i did the same just swapped examples
Original post by guccibananas
yes i did amino acids---->proteins
and monosaccharides------>glucose
is that okay?
I said proteins and amino acids. But then said Glycogen and alpha glucose as it’s monomers
Original post by guccibananas
yes i did amino acids---->proteins
and monosaccharides------>glucose
is that okay?
not on the spec
Original post by Tharris2001
A dimer
≤DNA helicase causes double helix to unwind
Hydrogen bonds break
free nucleotides join onto the exposed template by complementary base pairing
but this time A pairs with T and C pairs with the bird DNA.
catalysed by the enzyme DNA polymerase
H-bonds reform
Original post by Virolite
guys what did we write about the Thymine replacement 5 marker?
Reply 386
For the polymers monomers question
I talked about cellulose and beta glucose
Starch and alpha glucose
Reply 387
were you specific about the monosaccharides?
Reply 388
Yeah probably u will get some marks don’t worry
Original post by Danielle D
So they'd reduce like 2 marks right?
Reply 389
Original post by Haroon456
≤DNA helicase causes double helix to unwind
Hydrogen bonds break
free nucleotides join onto the exposed template by complementary base pairing
but this time A pairs with T and C pairs with the bird DNA.
catalysed by the enzyme DNA polymerase
H-bonds reform

Don’t you mean “this time A pairs with BdrU and C still pairs with G”? Since it was replacing thymine nucleotides. Also how many marks was this one?
Which value did you get?
when I converted the cm3 into mm3 I didn’t get any of the values listed.
Original post by jakehill_01
Immunology Question they gave CD4 concentration in cm^3 and the virus concentration in mm^3. VERY sneaky I almost missed it.
Original post by Haroon456
≤DNA helicase causes double helix to unwind
Hydrogen bonds break
free nucleotides join onto the exposed template by complementary base pairing
but this time A pairs with T and C pairs with the bird DNA.
catalysed by the enzyme DNA polymerase
H-bonds reform


I’m pretty sure that A would pair with the BrdU as C and G would still pair up. Thymine is complementary to A
Don’t think clear is an answer think it should be a important metabolite used in hydrolysis reactions, HIV doesn’t have a matrix but you should get all four other marking points
Original post by Pass&fail
Don’t remember it all but

Water Q -
High Specific heat capacity
Latent heat of vaporisation - allows cooling and homeostatic control
Solvent - o2 and co2 can easily dissolve into it making it a good support medium
Clear - allows photosynthetic organisms to create much needed glucose whilst encompassed by water.
Cohension tension - H bonds formed allows water to flow in xylem tissue

Biological tests Q
-Amylase (protein)
Add Naoh
Add biuret reagent
Purple colour

- Non reducing sugar:
add dilute HCL
warm for 5 mins
Add sodium hydrogen carbonate to neutralise
Add Benedicts reagent in equal volumes
Orange-brown colour

Lipids
Crush
Add to ethanol
Shake
Add to water
Shake
White emulsion

Last Q
Formed by condensation
Broken by hydrolysis

Example of Starch and monomers of B-Glucose

HIV Q:
Attachment proteins to bind to CD4 receptor
Lipid envelope
Matrix
Capisid with RNA and reverse transcriptase inside
(I drew a diagram)

How is haemoglobin different to help with increased metabolic rate in mice v horse?
- mouse has low affinity haem
- allows the o2 to dissociate easier at tissues
- increased o2 conc compared to horses
- so more respiration occurring relative to the horse

How does SA:V ratio affect the metabolic rate
- respiration causes heat.
- mouse has high metabolic rate but a high SA:V ratio so can cool easier due to evaporation
- horse has a low SA:V ratio meaning metabolic rate has to be slow so it doesn’t overheat as otherwise wouldn’t be able to have constant body temp

0.8 , 19.2

106 for the amount in median sample of blood (can’t really remember this Q)

Water was a limiting reagent in plants grown with little water
Less photosynthesis to create the glucose
6co2 + 6H2o —> 6c6h12o6 + 6o2
So less growth and ATP for mitosis

15.18 x faster for the metabolic rate Q

-HIV coordinators still had high levels of CD4 receptors which meant they still had good levels of Thelper cells
-AIDS suffers did not have high levels so couldn’t create an effective immune response against the high viral load once the HIV had come out of dormancy
Reply 393
Original post by tsunderhi_
Google it, the only dispute would be that its not enough to be a polymer but would aqa really delve in that deep? Because technically it is a polymer as its made from a monomer. Like if its not a polymer then what is it😂

image.jpg Polymers and monomers 😊and the definition in the aqa book of a polymer is LONG chains on monomer subunits
Maltose is a disaccharide , starch is a polysaccharide
Original post by Fezza101
I’m pretty sure that A would pair with the BrdU as C and G would still pair up. Thymine is complementary to A


Original post by tsunderhi_
Maltose is a polymer of glucose.
there would still be thymine on the dna formed though from the template strand
Original post by Azeee
Don’t you mean “this time A pairs with BdrU and C still pairs with G”? Since it was replacing thymine nucleotides. Also how many marks was this one?
Original post by Azeee
Don’t you mean “this time A pairs with BdrU and C still pairs with G”? Since it was replacing thymine nucleotides. Also how many marks was this one?


Yeah I can't remember which way it was on the question and Im pretty sure 5 marks
Reply 397
What was question 1 I don’t remember any of it except the first part someone
Reply 398
Original post by Maximoosey
there would still be thymine on the dna formed though from the template strand


Yeah but on the complementary strand there’s bdru which the scientists can detect, doesn’t matter if thymine still on original
Reply 399
non-competitive inhibitors of enzymes

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