ra1500
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RDKGames
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(Original post by ra1500)
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You need to show that the vector DE is a multiple of the vector BC.

EDIT: Or perhaps the expected approach is to show that the gradients are the same.
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Muttley79
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(Original post by ra1500)
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Can you copy what you wrote please? If this is mathswatch then it's a case of finding the right vocab.
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ra1500
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2/4=0.5
BC gradient is 2
AB (3,2)
AC (1,1)
DE gradient is 1/2=0.5
same gradients
parallel line have the same gradients
DE=0.5
BC=0.5
(Original post by Muttley79)
Can you copy what you wrote please? If this is mathswatch then it's a case of finding the right vocab.
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Muttley79
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(Original post by ra1500)
2/4=0.5
BC gradient is 2
AB (3,2)
AC (1,1)
DE gradient is 1/2=0.5
same gradients
parallel line have the same gradients
DE=0.5
BC=0.5
I think you need to show more steps and BC gradient is not correct.
D has coordinate (3,2) and E has coordinate (1,1)
Gradient of DE = (2 - 1)/(3 - 1) = 0.5
Gradient of BC = (-2 - -4)/(3 - 1) = 0.5
BC and DE have the same gradient so they are parallel.
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