The Student Room Group

Reply 1

First you have to standardize, it so u can work out the z score.
So its x - mu / sigma (st dev which is 10/the square root of 4)

190 - 185 / 10 = z < 1 then just read of the z score from your tables

is this what it says in your mark scheme?

Reply 2

oooooooo i see.. it said that but it didnt say about finding the standard dev, just the calculation so i was a bit confused. thanks a lot mate! x

Reply 3

actually my bad it says..
(190-185)/5 as (10^2)/4=25
what formula did u use to calculate variance when given mean? x

Reply 4

Im not quite sure what your looking for here. Is the distribution approximately normal? then the variance is st dev squared divided by n.

Did i actually get the question wrong then?

Reply 5

omg!!! i just started a thread asking the exact same question! LOL

Reply 6

yes mate u are right but as its standard deviation squared divided by n, its 10 squared over 4 which is 25. which means sd is 5 not 10. so it is 190-185 all over 5 which is 1 which is the right answer, cheers for your help x

Reply 7

Ahhhhh right yehh i see. Thanx for clearing that up.

Good Luck tomorrow !!!!!

Reply 8

its cool man, thanks :biggrin: x

Reply 9

Hi, how could I do this with a graphical calculator? (Casio fx-9750GII if it helps) Thanks

Reply 10

Never mind, I worked it out.
(For the benefit of anyone else who needs it, you do Normal C.D., set the lower to 190, upper to 1000000, sigma to 5 and mu to 185 and it'll give you the right answer)