How to integrate brackets Watch

DunDomi19
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how do you integrate the question ∫5(2x-4)^4dx. I know the equation about raise the power by 1 and having that as the denominator, however am nsure what to do when the constant is out the front of the brackets.
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RDKGames
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(Original post by DunDomi19)
how do you integrate the question ∫5(2x-4)^4dx. I know the equation about raise the power by 1 and having that as the denominator, however am nsure what to do when the constant is out the front of the brackets.
It's just a constant. You can just move it outside: \displaystyle 5\int (2x-4)^4 .dx. So obviously it has no effect on how you integrate, you just need to remember that it multiplies whatever result you get after integration.

Also, the integration here isn't as simple as "raising the power by 1 and dividing by it". Have a go yourself but to check whether you get it right, you should differentiate your result and expect to obtain the same expression as the integrand.
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