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Fayeeeee
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I’m not sure how to do 2 Attachment 802982Attachment 802984
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RDKGames
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(Original post by Fayeeeee)
I’m not sure how to do 2
An odd number represented algebraically is 2n+1, so what is (2n+1)^3 ?
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Fayeeeee
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(Original post by RDKGames)
An odd number represented algebraically is 2n+1, so what is (2n+1)^3 ?
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Fayeeeee
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(Original post by RDKGames)
An odd number represented algebraically is 2n+1, so what is (2n+1)^3 ?
Also I don’t really understand 5 Name:  409B64AB-B6F6-459E-BFEB-3D911F9234E5.jpg.jpeg
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RDKGames
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(Original post by Fayeeeee)
is that right
Yeah that's right. To show that it's an odd number, you should explicitly try and get it into the form:

2 \times \text{(something)} + 1.
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RDKGames
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(Original post by Fayeeeee)
Also I don’t really understand 5
Look at the LHS. Is it an even or an odd number??

Then that must be the case for the RHS, and since 5 is an odd number, it leaves only one option as to whether x is even or odd.
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Fayeeeee
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(Original post by RDKGames)
Yeah that's right. To show that it's an odd number, you should explicitly try and get it into the form:

2 \times \text{(something)} + 1.
Ahh okay thanks
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Fayeeeee
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(Original post by RDKGames)
Look at the LHS. Is it an even or an odd number??

Then that must be the case for the RHS, and since 5 is an odd number, it leaves only one option as to whether x is even or odd.
I know x is an odd number but I don’t understand how to get it into that from
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RDKGames
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(Original post by Fayeeeee)
I know x is an odd number but I don’t understand how to get it into that from
You don't need to get x into the form 2n+1, if that's what you're asking.

In this question you don't use algebra to answer it so no need to introduce that form.
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Fayeeeee
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(Original post by RDKGames)
You don't need to get x into the form 2n+1, if that's what you're asking.

In this question you don't use algebra to answer it so no need to introduce that form.
I don’t know what to do, do I rearrange idk
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RDKGames
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(Original post by Fayeeeee)
I don’t know what to do, do I rearrange idk
You just said you know that x is odd. [which I'm interpreting as you telling me you have logically deduced this is true]

You have answered the question and don't need to do anything further!
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Fayeeeee
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(Original post by RDKGames)
You just said you know that x is odd. [which I'm interpreting as you telling me you have logically deduced this is true]

You have answered the question and don't need to do anything further!
I need to put it into this form Name:  F055199B-C78D-4727-8F11-4C4D262F6B3C.jpg.jpeg
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(Original post by Fayeeeee)
I need to put it into this form
Ok, well they took the algebraic approach.

Do you understand how to start at 2(x-n) = x+5 and rearrange for x, first of all?
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(Original post by RDKGames)
Ok, well they took the algebraic approach.

Do you understand how to start at 2(x-n) = x+5 and rearrange for x, first of all?
No😂
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(Original post by Fayeeeee)
No😂
Expand the LHS first.

Then have a go.
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(Original post by RDKGames)
Expand the LHS first.

Then have a go.
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(Original post by Fayeeeee)
...
Come on...

Subtract x from both sides...
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Fayeeeee
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(Original post by RDKGames)
Come on...

Subtract x from both sides...
i don’t understand why in the mark scheme the brackets has n+2 as u thought odd numbers could only be n+1,n+3 for example
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(Original post by Fayeeeee)
i don’t understand why in the mark scheme the brackets has n+2 as u thought odd numbers could only be n+1,n+3 for example
I meant as I
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(Original post by Fayeeeee)
i don’t understand why in the mark scheme the brackets has n+2 as u thought odd numbers could only be n+1,n+3 for example
No, odd numbers (as I've mentioned previously!) are of the form 2 \times \text{(something)} + 1 so in this question, the 'something' is precisely n+2.

This 'something' can be whatever as long as it's an integer, and n+2 is definitely an integer. So that's no issue!
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