Trig question help?Watch

#1
The equation is: (sec^2x -5)(1-cos2x) = tan^2xsin2x
I've been trying to convert (1-cos2x) into a factor of tan^2xsin2x so that I can divide everything through and simplify it but I'm not sure how to do this.
0
1 week ago
#2
(Original post by 67chevvyimpala)
The equation is: (sec^2x -5)(1-cos2x) = tan^2xsin2x
I've been trying to convert (1-cos2x) into a factor of tan^2xsin2x so that I can divide everything through and simplify it but I'm not sure how to do this.
I don't think it's going to convert directly into a factor of the RHS.

I suggest splitting all the double angles.

The obvious one for 1-cos2x is
1 week ago
#3
are you trying to solve the equation or prove the identity of LHS to RHS ?

0
#4
(Original post by ghostwalker)
I don't think it's going to convert directly into a factor of the RHS.

I suggest splitting all the double angles.

The obvious one for 1-cos2x is

I've finally figured it out
Thanks!
Last edited by 67chevvyimpala; 1 week ago
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