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67chevvyimpala
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The equation is: (sec^2x -5)(1-cos2x) = tan^2xsin2x
I've been trying to convert (1-cos2x) into a factor of tan^2xsin2x so that I can divide everything through and simplify it but I'm not sure how to do this.
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ghostwalker
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(Original post by 67chevvyimpala)
The equation is: (sec^2x -5)(1-cos2x) = tan^2xsin2x
I've been trying to convert (1-cos2x) into a factor of tan^2xsin2x so that I can divide everything through and simplify it but I'm not sure how to do this.
I don't think it's going to convert directly into a factor of the RHS.

I suggest splitting all the double angles.

The obvious one for 1-cos2x is 2sin^2x
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the bear
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are you trying to solve the equation or prove the identity of LHS to RHS ?

:holmes:
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67chevvyimpala
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(Original post by ghostwalker)
I don't think it's going to convert directly into a factor of the RHS.

I suggest splitting all the double angles.

The obvious one for 1-cos2x is 2sin^2x

I've finally figured it out
Thanks!
Last edited by 67chevvyimpala; 1 week ago
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