The Student Room Group

rearranging an equation to make a particular variable the subject.

xy=1

(t^2)x-y=t^3-1/t

I have tried putting x=1/y into the bottom equation but it gets messy. Is there another way of doing this. I do not want the solution, just a helpful pointer. Thanks in advance.
(edited 5 years ago)
Original post by chatterclaw73
xy=1

t^2x-y=t^3-1/t

I have tried putting x=1/y into the bottom equation but it gets messy. Is there another way of doing this. I do not want the solution, just a helpful pointer. Thanks in advance.


What is the actual question?
Original post by Muttley79
What is the actual question?


Express x and y in terms of the other variable.
I have edited the original post in case of confusion.
(edited 5 years ago)
Original post by chatterclaw73
Express x and y in terms of the other variable.
I have edited the original post in case of confusion.


Where does this come from? Is this the whole question?
It is the entire question. The question comes from a CD-ROM extension exercise for OCR C1. It is an old spec(2004). I am studying for pleasure rather than towards an exam. I have been asked this a few times on this site. Is it permitted to ask questions unless you are studying towards a goal? If so I apologise. I just love maths and am keen to understand.
Original post by Muttley79
Where does this come from? Is this the whole question?
Original post by chatterclaw73
It is the entire question. The question comes from a CD-ROM extension exercise for OCR C1. It is an old spec(2004). I am studying for pleasure rather than towards an exam. I have been asked this a few times on this site. Is it permitted to ask questions unless you are studying towards a goal? If so I apologise. I just love maths and am keen to understand.

It's fine to study for fun but this question is not C1 level and seems very strange to me. I wonder if there is an error - what are the answers supposed to be?
(x=t,y=1/t), (x=-1/t^3,y=-t^3). I have had this response from other members of this forum, to different questions from the same book. As I mentioned it is not required C1 learning. The CD is designed to test the more able pupils. you may ask why then am I attempting these questions!! I just love to learn.
Original post by Muttley79
It's fine to study for fun but this question is not C1 level and seems very strange to me. I wonder if there is an error - what are the answers supposed to be?
Original post by chatterclaw73
(x=t,y=1/t), (x=-1/t^3,y=-t^3). I have had this response from other members of this forum, to different questions from the same book. As I mentioned it is not required C1 learning. The CD is designed to test the more able pupils. you may ask why then am I attempting these questions!! I just love to learn.


OL - I substitute y = 1/x then multiplied through by x and t.

I got a quadratic that I could factorise.
Original post by Muttley79
OL - I substitute y = 1/x then multiplied through by x and t.

I got a quadratic that I could factorise.


Thanks a lot. I actually did this before but I was thinking of a quadratic in t! After finding a quadratic in x and using the formula, the algebra was still a bit hard but I got there. Once again thanks a lot. I am quite new to this site so I do not know how to rep you. It goes without saying that I would if I knew.
Original post by chatterclaw73
Thanks a lot. I actually did this before but I was thinking of a quadratic in t! After finding a quadratic in x and using the formula, the algebra was still a bit hard but I got there. Once again thanks a lot. I am quite new to this site so I do not know how to rep you. It goes without saying that I would if I knew.


It actually factorises [(t^3) x + 1][ x - t ] which is easier than the formula - to rep a post you click on the grey circle underneath any post :smile:

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