Bertybassett
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Hello, for the reaction of aluminium hydroxide with excess oh-, I know that this forms Al(oh)4(h2o)- , but what is the actual reaction for this (equation)? Also, what's the reaction equation of copper hydroxide with excess ammonia? As well as that, I know the overall reactions of hexa aqua ions with the carbonate ion, but what happens to the "other" ion in the equation e.g. the na+ in sodium carbonate? where does this go and what does it react with? Many thanks
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BobbJo
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Al(H2O)3(OH)3 + OH- -> [Al(H2O)2(OH)4]- + H2O

Cu(H2O)4(OH)2 + 4NH3 -> [Cu(H2O)2(NH3)4]2+ + 2H2O + 2 OH-

[Cu(H2O)6]2+ + Na2CO3 -> [Cu(H2O)6]2+CO32- + 2Na+
Na+ is a spectator ion. It stays in solution
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