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Here's a link to the question https://pmt.physicsandmathstutor.com...0Functions.pdf
June 2011 Q4b
Why isn't the domain X is any real number
June 2011 Q4b
Why isn't the domain X is any real number
Last edited by JacobBob; 1 year ago
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#2
(Original post by JacobBob)
Here's a link to the question https://pmt.physicsandmathstutor.com...0Functions.pdf
Jan 2012 Q7b
Why isn't the domain X is any real number
Here's a link to the question https://pmt.physicsandmathstutor.com...0Functions.pdf
Jan 2012 Q7b
Why isn't the domain X is any real number
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(Original post by Muttley79)
When x = 1 the denominator is zero and the function undefined.
When x = 1 the denominator is zero and the function undefined.
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#4
(Original post by JacobBob)
Oh god, I'm sorry, I meant June 2011 Q4b
Oh god, I'm sorry, I meant June 2011 Q4b
without any other information then yes the domain would be 
.But
is defined based on 
. The domain of is restricted to 
which gives you a range of 
. This must mean that the domain of is 
.The domain of
is always the range of and vice-versa. So if you are asked for the domain/range of an inverse function then you should always get these from the domain/range of the original function.
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(Original post by Notnek)
If you were given the function without any other information then yes the domain would be .
But is defined based on . The domain of is restricted to which gives you a range of . This must mean that the domain of is .
The domain of is always the range of and vice-versa. So if you are asked for the domain/range of an inverse function then you should always get these from the domain/range of the original function.
If you were given the function
without any other information then yes the domain would be .But
is defined based on . The domain of is restricted to which gives you a range of . This must mean that the domain of is .The domain of
is always the range of and vice-versa. So if you are asked for the domain/range of an inverse function then you should always get these from the domain/range of the original function.
I found the range of fx to be y<0 so I took the domain of f inverse x as x<0
But the answer in the mark scheme is x>0 so I'm confused
I found the range by "forming the function" using the domain they had given me
2x-1>0
and then I flipped it to get y<0
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#6
(Original post by JacobBob)
In 2012 Jan 7c
I found the range of fx to be y<0 so I took the domain of f inverse x as x<0
But the answer in the mark scheme is x>0 so I'm confused
I found the range by "forming the function" using the domain they had given me
2x-1>0
and then I flipped it to get y<0
In 2012 Jan 7c
I found the range of fx to be y<0 so I took the domain of f inverse x as x<0
But the answer in the mark scheme is x>0 so I'm confused
I found the range by "forming the function" using the domain they had given me
2x-1>0
and then I flipped it to get y<0
0
reply
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