engineering mechanics help
A box (weighing Mg) is hanging on a rope (looks like 2 rope forming an upside down triangle with the ceiling) making it sag by 2 metres. the distance betwen the ropes is 5 metres.
Determine the tension to keep the box immobile and compare it with initial weight of the box.
N.B. no angles was given which is why I'm stuck. I have the answers but cannot get to it or understand it.
Determine the tension to keep the box immobile and compare it with initial weight of the box.
N.B. no angles was given which is why I'm stuck. I have the answers but cannot get to it or understand it.
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(edited 5 years ago)
Original post by zubz91
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On your diagram, x = 5m and y=2m, so you can work out angles (use tan).
Original post by old_teach
On your diagram, x = 5m and y=2m, so you can work out angles (use tan).
I'm not getting the same answer, which is T=157N where T = 80% of 196.2N (whatever that means)
Looks like you need to know the weight?
Are you ok that 2T cos theta = weight ?
(theta is angle to vertical of one T from centre)
Are you ok that 2T cos theta = weight ?
(theta is angle to vertical of one T from centre)
Original post by old_teach
Looks like you need to know the weight?
Are you ok that 2T cos theta = weight ?
(theta is angle to vertical of one T from centre)
Are you ok that 2T cos theta = weight ?
(theta is angle to vertical of one T from centre)
so we treat tension on both sides of the rope equal?
Yes, otherwise they'd be a resultant horizontal force.
Original post by old_teach
Yes, otherwise they'd be a resultant horizontal force.
ok but since I'm given length rather than newtons of the ropes, can I still use the distances to find theta?
The distances give you the ropes' angles.
The tension is applied by the ropes, so is along the same angle!
The tension is applied by the ropes, so is along the same angle!
Original post by old_teach
The distances give you the ropes' angles.
The tension is applied by the ropes, so is along the same angle!
The tension is applied by the ropes, so is along the same angle!
Thankyou so much for the help!!!! I finally got the same solution!!!
(edited 5 years ago)
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