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First Order Differential Equation Verification

I've tried the differential equations below plenty of times but my answers and the answer given in the textbook do not match. Can anyone please verify the answers for me? Thank you so much!

1) dvdt+av=ebt\frac{\mathrm{d} v}{\mathrm{d} t} + av = e^{bt}

2) sin(x)dydx+2ycos(x)=cos(x)\sin(x)\frac{\mathrm{d} y}{\mathrm{d} x} + 2y\cos(x) = \cos(x)

My answers (here, c is some arbitrary constant):

1) v=1a+b(ebteat)v = \dfrac{1}{a + b}(e^{bt} - e^{-at})

2) ysin2(x)=14cos(2x)+cy\sin^2(x) = -\dfrac{1}{4} \cos(2x) + c
(edited 5 years ago)
Original post by esrever
I've tried the differential equations below plenty of times but my answers and the answer given in the textbook do not match. Can anyone please verify the answers for me? Thank you so much!

1) dvdt+ay=ebt\frac{\mathrm{d} v}{\mathrm{d} t} + ay = e^{bt}

2) sin(x)dydx+2ycos(x)=cos(x)\sin(x)\frac{\mathrm{d} y}{\mathrm{d} x} + 2y\cos(x) = \cos(x)

My answers (here, c is some arbitrary constant):

1) v=1a+b(ebteat)v = \dfrac{1}{a + b}(e^{bt} - e^{-at})

2) ysin2(x)=14cos(2x)+cy\sin^2(x) = -\dfrac{1}{4} \cos(2x) + c


Did you write eqn.(1) correctly?

Solution 2 looks good. Rearrange it for yy since you can.
(edited 5 years ago)
Reply 2
Original post by RDKGames
Did you write eqn.(1) correctly?

Solution 2 looks good. Rearrange it for yy since you can.


Thank you so much! There was a small error in eqn(1). I have fixed it now.
Original post by esrever
Thank you so much! There was a small error in eqn(1). I have fixed it now.


Solution to eqn, 1 is good too if you include the arbitrary constant in the correct place.
Reply 4
Original post by RDKGames
Solution to eqn, 1 is good too if you include the arbitrary constant in the correct place.


Oh I forgot to include the arbitrary constant (took v = 0 at t = 0) instead. Thanks a lot for verifying :smile:.

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